Latest TCS Aptitude Question SOLUTION: three man walk around a cirlce of 1750 metres circumference at the rate of 160 m,120 m,105 m per minute respectively..if thet all start together and walk in same direction when the

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three man walk around a cirlce of 1750 metres circumference at the rate of 160 m,120 m,105 m per minute respectively..if thet all start together and walk in same direction when they will be together again for the first time??

Asked In TCS TargetTCS 2014 (11 years ago)

Unsolved Read Solution (9)

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sahithi  (11 years ago)

given speeds in meters/min so covert them to m/s
so, 160/60,120/60,105/60=8/3,2,7/4
they meet together again for first time =lcm(8/3,2,7/4)=lcm(8,2,7)/hcf(3,1,4)=56/1
ans:56sec

Is this solution Helpfull? Yes (29) | No (13)  

Chandra Bhatt  (11 years ago)

350 meters.

Is this solution Helpfull? Yes (11) | No (8)  

Himank Agrawal  (11 years ago)

Time taken by a,b and c to complete one round respectively are 175/16,175/12,1750/105 min. Now taking the lcm of these three time give us the time at which they all meet for the first time lcm(175,175,1750)/hcf(16,12,105)=1750 minutes or 10500seconds or you can also find out the distance using the above time.

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Vibhu Gaur  (11 years ago)

For these ques we find out the relative time of all runners w.r.t fastest runner and then take the LCM of all these times to get the time at which they all meet at first time
so T(AB)=1750/40=175/4 and T(AC)=1750/55=350/11
LCM of T(AB) & T(AC)= LCM(175 ,350)/HCF(4,11)= 350/1=350 min (ANS)

PS-10500 is correct ans when they meet at starting point for first time not when they meet first time

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rajesh ray  (11 years ago)

pls solution in details

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D G  (11 years ago)

160/60 , 120/60 , 105/60 = 8/3,2,7/4
choose one person as contant....and calculate relative speed....1750/(8/3-2) and 1750/(8/3-7/4)...we get 2625 and 2100/11.....lcm(2625,2100/11)= answr is 10500 secnds

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chirag jain  (11 years ago)

after 32mins.. take their lcm and divide by 105 because it is slowest.. and answer will come 32mins..

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Krati Agarwal  (11 years ago)

at 141 m?

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QuickSilver  (11 years ago)

They will meet in (175/12) or 14.583 minutes or at 2333.33 metres

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