Latest TCS Aptitude Question SOLUTION: In a eucldian triangle one side is 20 and one of its others sides is 10... given the area is 80 what is the third side?

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In a eucldian triangle one side is 20 and one of its others sides is 10... given the area is 80 what is the third side?

Asked In TCS pravallika nathi (11 years ago)

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Kundan Kumar  (11 years ago)

Fisrtly, Draw the the triagle. Now
Using Relation A= 1/2*a *b* SinC put (A=80,a=20,b=10)
We can calculate the value of SinC which is equal to 4/5
Since, SinC=4/5 therefore, CosC= 3/5
Now using Cosine rule
c^2=a^2+b^2-2abCosC..
Now put the values
C=2sqrt65
ie.16.12

Is this solution Helpfull? Yes (20) | No   

tejaswi boni  (11 years ago)

Area of triangle A=sqrt of s(s-a)(s-b)(s-c).
where s=(a+b+c)/2.
here a=20,b=10,A=80.
therefore s=15+c/2.
80^2=(15+c/2)(c/2-5)(c/2+5)(15-c/2)
c=16.12.

Is this solution Helpfull? Yes (15) | No (1)  

swagatika sahoo  (11 years ago)

let 20 be the base,and other side of the triangle be 10,draw a perpendicular to the base which height will be h=8 as(1/2*20*h=80 given),
the base is two parts now x & 20-x,putting pythagoras theorem we can get x 10^2=8^2+x^2 so x=6,
other part of base is 20-6=14,
now we can get the other part of the triangle 14^2+8^2=64 i.e 8
hence the other side is 8.

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Rohit Joshi  (11 years ago)

let 10 be the base and draw a perpendicual on it so height will come 16.
now we get a right triangle with height 16 and one side 20 so we can get base which comes out 12.
10 is one side so 2 will be an extension for the perpendicular drawn.height=16 perpendicular =16 so third side =root(16*16+2*2)=root260

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