Latest TCS Aptitude Question SOLUTION: A software engineer starts from home at 3 PM for evening walk on a route which has level road for some distance and a then a hillock. He walks speed of 4kmph on level ground and th

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A software engineer starts from home at 3 PM for evening walk on a route which has level road for some distance and a then a hillock. He walks speed of 4kmph on level ground and then at a speed of 3kmph on the uphill and then down the hill at a speed of 6 kmph to the level ground and then at a speed of 4kmph to the home If he reaches home at 9 PM. What is the distance one way of his route?
option
(A) 12 Km
(B) 15 Km
(C) 18 Km
(D) 24 Km
(E) Data Inadequate

Asked In TCS ASD (10 years ago)

Unsolved Read Solution (4)

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Read Solution (4) :

roja  (10 years ago)

ans is 12kms....
let the distance travelled in level ground is x kms in t hrs...
then x=4t....
let distance travelled in the hillock is y kms in (t+a)hrs....
then y=3(t+a)....
back to the house distanc in hillock is 6(t-a)kms...
in the level ground is 4t....
total time taken to reach home is 6hrs...
t+(t+a)+(t-a)+t=6 there4 t=3/2....
distance from and is same there4 by equating 4t+3(t+a)=4t+6(t-a)
ie...a=1/2...
distance from house to hillock is 12kms....

Is this solution Helpfull? Yes (28) | No (6)  

anamika  (10 years ago)

ans is 12. sorry..

Is this solution Helpfull? Yes (2) | No (1)  

anamika  (10 years ago)

i think ans should be 10km.. but its not in the option :(

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anmol  (5 years ago)

@ROJA
your method is right
answer is wrong
Answer is 24

X=4T---------2 TIMES -----> GIVES 12( 6 EACH )
Y=6(T-A) ------> GIVES 6
Y=3(T+A)-------> GIVES 6
therefore total 24
(value of A = 1/2 && T = 3/2)

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