Latest Wipro Aptitude Question SOLUTION: An empty tank be filled with an inlet pipe A in 42 minutes. After 12 minutes an outlet pipe B is opened which can empty the tank in 30 minutes. After 6 minutes another inlet pipe C

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An empty tank be filled with an inlet pipe A in 42 minutes. After 12 minutes an outlet pipe B is opened which can empty the tank in 30 minutes. After 6 minutes another inlet pipe C opened into the same tank, which can fill the tank in 35 minutes and the tank is filled. Find the time taken to fill the tank?

Asked In Wipro supreetha bhushan (10 years ago)

Unsolved Read Solution (9)

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Read Solution (9) :

Ganesh Bhat  (10 years ago)

For first 12 mins tank is 2/7 filled(because only pipe A is opened). For first 18 mins tank is 8/35 filled. i.e pipe A is opened for 18 mins and pipe B is opened for 6 mins. (3/7)-(1/5)=8/35. that means after 18 mins tank is 8/35 filled.
so, after 18 mins all the 3 pipes work simultaneously.
now we calculate the time required to fill the tank by 3 pipes,
(1/42)+(1/35)-(1/30)=2/105. It means 105/2 mins.
But the tank is already 8/35 filled. so,we have to find the time required to fill 27/35 of the tank.
time taken to fill 27/35 of the tank=(105/2)*(27/35)= 40.5 mins.
time taken to fill the tank= 18 mins+40.5 mins = 58.5 mins.
Ans:58.5 mins

Is this solution Helpfull? Yes (20) | No (5)  

parkv36  (10 years ago)

pipe A is open for 12 mins, so (12/42)=(2/7) of the tank is filled. pipe A and B are open together for the next 6 mins. So 6((1/42)-(1/30))+(2/7)= (8/35) is filled in 18 mins. then all three pipes are open together. they can fill (1/42)-(1/30)+(1/35)=(2/105) of the tank. now only 1-(8/35)=(27/35) needs to be filled. So time taken to fill the remaining part is (27/35)/(2/105)=40.5 mins.
total time = 18+40.5 = 58.5 mins

Is this solution Helpfull? Yes (9) | No   

jitendra singh  (10 years ago)

58.5 minute

Is this solution Helpfull? Yes (4) | No (2)  

Saurabh Mishra  (10 years ago)

let total capicity of tank =100 and total time=t
so t(10042)-(t-12)(1030)+(t-18)(10035)=100
on solving this equation we get t=58.52
so t=58.52

Is this solution Helpfull? Yes (4) | No (1)  

Sridevi SV  (9 years ago)

Pipe A in one minute fills 1/42 of the tank. Pipe A is totally kept open for 12 + 6 -> 18 minutes before Pipe C is opened. Thus in 18 minutes Pipe A fills 18/42 -> 3/7 capacity of the tank.

Pipe B can drain the tank in 30 minutes and in one minute can drain 1/30 of the tank.

Pipe B is kept open for 6 minutes before Pipe C is opened. In this 6 minutes it would have drained 6/30 -> 1/5 capacity of the tank.

Hence, after 18 minutes the tank is filled up to – > 3/7 – 1/5 -> 8/35 capacity.

The remaining capacity to be filled is -> 27/35

All the three pipes are now running to fill this quantity.

Pipe C in one minute can fill 1/35 capacity.

Now in one minute both Pipes A and C fills and C drains. The quantum filled in one

Minute is -> 1/42 + 1/35 – 1/30 -> 2/70.

Thus to fill the remaining capacity of 27/35 the time taken will be 27/35 * 70/2 -> 27 minutes.

Hence, the total time taken to fill the tank is 12 + 6 + 27 = 45 minutes.

Is this solution Helpfull? Yes (1) | No (3)  

satish  (9 years ago)

first take the lcm of 42,30and 35 we will get an 210
take this has units i.e 210 units
a=210/42 = 5
B = 210/ 30 = 7
c= 210/35 = 6
till 18 min A is opened and only 6min b is opened then
5*18=90 and 7*6=42
90-42=48
210-48=162
if a=5,b=-7 c=6
then a+b+c = 4
162/4 = 40.5
18+40.5 = 58.5

Is this solution Helpfull? Yes (1) | No   

mounika  (10 years ago)

could any one explain...i am getting 35.5 mins

Is this solution Helpfull? Yes | No (4)  

pavan srinivas  (10 years ago)

please expalin these question clearly and step by step process

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anurag  (9 years ago)

45mins is the correct 200% sure

Is this solution Helpfull? Yes | No (2)  

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