Latest TCS Aptitude Question SOLUTION: dhiman is trying to hone his skills on counting and comes across the following problem. How many 4 digit numbers are divisible by 5 with all the digits distinct? In the options bel

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dhiman is trying to hone his skills on counting and comes across the following problem.
How many 4 digit numbers are divisible by 5 with all the digits distinct? In the options below, n! = 1*2*...*n is the factorial function (e.g. 4! = 24).
His answer would be :
18*9!/7!
9!/6!
8*8!/6!
16*8!/6!
17*8!/6!

Asked In TCS (10 years ago)

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abhinav paul  (10 years ago)

ans should be D..
suppose 0 is at unit place. then, numbers can be formed as- 9*8*7*1
if we say 5 is at unit place, then numbers can be formed as- 8*8*7*1
so, total cases is sum of these.
case I can b written as- 9!/6!=9*(8!/6!) and case II can be written as 8*(8!/6!)
taking common out- (9+8)8!/6! = 17(8!/6!)

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Guru Pranav  (10 years ago)

9*8*7*1 + 8*8*7*1

= 17(8!/6!)

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