Latest TCS Aptitude Question SOLUTION: Let v1 = 1, v2 = 4, v3 = 7, v4 = 6, v5 = 12. Let u1, u2, u3, u4, u5 represent the same numbers in a different order. Consider the product P = (u1 - v1)(u2 - v2)(u3 - v3)(u4 - v4)(u

• Placement Papers
• /
• TCS
• /
• Logical Reasoning
• /
• Logical Sequences

TCS Question Papers: TCS Interview Experience(91) TCS Company Profile

(#M40026340) TCS Logical Reasoning question Keep an EYE

Let v1 = 1, v2 = 4, v3 = 7, v4 = 6, v5 = 12. Let u1, u2, u3, u4, u5 represent the same numbers in a different order. Consider the product P = (u1 - v1)(u2 - v2)(u3 - v3)(u4 - v4)(u5 - v5), Then
option
a) P is always even.
b) P is always negative
c) P is always positive
d) P is even or odd depending on the ordering
e) P is always odd

Asked In TCS (11 years ago)

Unsolved Read Solution (10)

Is this Puzzle helpful?   (6)   (0) Submit Your Solution Logical Sequences

Read Solution (10) :

hardik  (11 years ago)

p is always even

Is this solution Helpfull? Yes (32) | No (11)  

kumar  (11 years ago)

there are no fixed rule for this type of question
we have to solve this question with the help of option
a)take order of u1,u2,...=12,1,4,7,6 then p=(11)*(-3)*(-3)*(1)*(-6)=odd
option a wrong

b)take order of u1,u2,....=12,6,1,7,4 then=p=11*2*-6*1*-8= +ve
option b wrong

c)take order of u1,u2,...=12,1,4,7,6 then p=(11)*(-3)*(-3)*(1)*(-6)= -ve
option c wrong

d)take order of u1,u2,....=7,6,1,12,4 then p=6*2*-6*6*-8=even no
correct ans because in option 1 we proved that it may be odd no ,and here we proved that it may be even number.

e)in option d we proved that it may be even no
wrong option


final ans will be (d)

Is this solution Helpfull? Yes (24) | No (10)  

C.Suneel Kumar Reddy  (11 years ago)

ans is : pis always even .

Is this solution Helpfull? Yes (4) | No (4)  

Md Shahnawaz Shahab  (11 years ago)

P is always even.
P is always negative.

both the above statements are true.

Is this solution Helpfull? Yes (3) | No (15)  

Tanu  (11 years ago)

Someone Please explain how P is always even
Let we change the order as 4 1 7 6 12
So P=3*(-3)*0*0*0=0 and 0 is odd....there are many cases where P is odd

Is this solution Helpfull? Yes (2) | No (5)  

M Sri Raviteja  (11 years ago)

p is always even

Is this solution Helpfull? Yes (2) | No (1)  

prafull mittal  (11 years ago)

p is always even

Is this solution Helpfull? Yes (2) | No   

shikha gupta  (11 years ago)

0 is not an odd number @tanu

Is this solution Helpfull? Yes (1) | No (1)  

Tanu  (11 years ago)

@shikha gupta oh ya thnx for pointing it out bt still there are other cases where P can b odd.

Is this solution Helpfull? Yes (1) | No (1)  

shrishty choudhry  (11 years ago)

there are no fixed rule for this type of question
we have to solve this question with the help of option
a)take order of u1,u2,...=12,1,4,7,6 then p=(11)*(-3)*(-3)*(1)*(-6)=odd
option a wrong

b)take order of u1,u2,....=12,6,1,7,4 then=p=11*2*-6*1*-8= +ve
option b wrong

c)take order of u1,u2,...=12,1,4,7,6 then p=(11)*(-3)*(-3)*(1)*(-6)= -ve
option c wrong

d)take order of u1,u2,....=7,6,1,12,4 then p=6*2*-6*6*-8=even no
correct ans because in option 1 we proved that it may be odd no ,and here we proved that it may be even number.

e)in option d we proved that it may be even no
wrong option


final ans will be (d)

Is this solution Helpfull? Yes (1) | No   

Please Login to Read Solution.