Latest Wipro Aptitude Question SOLUTION: Two Equal Amounts of Money are lent out at 6% and 5 % simple Interest respectively at the same time. The former is recovered two years earlier than the latter and the amount so rec

• Placement Papers
• /
• Wipro
• /
• Numerical Ability
• /
• Simple & Compound Interest

Wipro Question Papers: Wipro Interview Experience(2) WIPRO Company Profile

(#M40026397) WIPRO Numerical Ability question Keep an EYE

Two Equal Amounts of Money are lent out at 6% and 5 % simple Interest respectively at the same time. The former is recovered two years earlier than the latter and the amount so recovered in each case is RS, 2800. Determine the amount that is lent out?
A) 1950
B) 1500
C) 1800
D) 1375

Asked In Wipro chaitanya (10 years ago)

Unsolved Read Solution (5)

Is this Puzzle helpful?   (8)   (15) Submit Your Solution Simple & Compound Interest

Read Solution (5) :

Dr.Dipin Singh  (10 years ago)

Rs 1750 in each case which is not given in the options.
check
Interest in each case = 1750*6*10/100 = 1750*5*12/100 = Rs 1050

Is this solution Helpfull? Yes (9) | No (16)  

ruchi shah  (10 years ago)

Ans: Rs.1800
let p be the amount lent out
interest in 1st case= p*r*t/100
= p*6*t/100
=6pt/100------------------(equation 1)
interest in 2nd case= p*r*t/100
=p*5*(t+2)/100 (since recovered 2 years later than 1st one)
since amounts are equal(each 2880) and lent out sums are equal, intersts will be equal
=> 5p(t+2)/100=6pt/100
=>5t+10=6t
=>t=10yrs
final amt=2880
=>p + interst = 2880
=> p + 5p*12/100 = 2800
=>160p=2800*100
=> p= Rs.1750

Is this solution Helpfull? Yes (9) | No (3)  

chiranjib goswami  (10 years ago)

Ans: Rs.1800
let p be the amount lent out
interest in 1st case= p*r*t/100
= p*6*t/100
=6pt/100------------------(equation 1)
interest in 2nd case= p*r*t/100
=p*5*(t+2)/100 (since recovered 2 years later than 1st one)
since amounts are equal(each 2880) and lent out sums are equal, intersts will be equal
=> 5p(t+2)/100=6pt/100
=>5t+10=6t
=>t=10yrs
final amt=2880
=>p + interst = 2880
=> p + 5p*12/100 = 2880
=>160p=2880*100
=> p= Rs.1800

Is this solution Helpfull? Yes (5) | No (1)  

saiteja makani  (10 years ago)

Ans: Rs.1800
let p be the amount lent out
interest in 1st case= p*r*t/100
= p*6*t/100
=6pt/100------------------(equation 1)
interest in 2nd case= p*r*t/100
=p*5*(t+2)/100 (since recovered 2 years later than 1st one)
since amounts are equal(each 2880) and lent out sums are equal, intersts will be equal
=> 5p(t+2)/100=6pt/100
=>5t+10=6t
=>t=10yrs
final amt=2880
=>p + interst = 2880
=> p + 6p*10/100 = 2880
=>16p=2880*10
=> p= Rs.1800

Is this solution Helpfull? Yes (3) | No (2)  

sajid  (10 years ago)

ans will be 1750

Is this solution Helpfull? Yes (1) | No (2)  

Please Login to Read Solution.