Latest IIT-JEE Aptitude Question SOLUTION: A thin ring of mass 2 kg and radius 0.5 m is rolling without on a horizontal plane with velocity 1 m/s. A small ball of mass 0.1 kg, moving with velocity 20 m/s in the opposite dir

Follow Quotesrain

IIT-JEE Question Papers:

IIT-JEE Select Another Category Select Another Topic

Exam

IIT-JEE Question Topics

Category (1)

HR Interview (1)

Interview(1)

Logical Reasoning (3)

Numerical Ability (12)

Verbal Ability (1)

Advertisements

Previous Question: Two solid spheres A and B of equal volumes but of different densities dA and dB are connected by a string. They are fully immersed in a fluid of density dF. They get arranged into an equilibrium state as shown in the figure with a tension in the string. The arrangement is possible only if (A) dA < dF (B) dB > dF (C) dA > dF (D) dA + dB = 2dF Next Question: Which of the following statement(s) is/are correct? (A) If the electric field due to a point charge varies as r-2.5 instead of r-2, then the Gauss law will still be valid. (B) The Gauss law can be used to calculate the field distribution around an electric dipole (C) If the electric field between two point charges is zero somewhere, then the sign of the two charges is the same. (D) The work done by the external force in moving a unit positive charge from point A at potential VA to point B at potential VB is (VB - VA).

(#M40027781) IIT-JEE question 2011 question Keep an EYE

A thin ring of mass 2 kg and radius 0.5 m is rolling without on
a horizontal plane with velocity 1 m/s. A small ball of mass
0.1 kg, moving with velocity 20 m/s in the opposite direction
hits the ring at a height of 0.75 m and goes vertically up with
velocity 10 m/s. Immediately after the collision

(A) the ring has pure rotation about its stationary CM.
(B) the ring comes to a complete stop.
(C) friction between the ring and the ground is to the left.
(D) there is no friction between the ring and the ground.: Asked In IIT-JEE MAN (10 years ago); Unsolved; Is this Puzzle helpful? (1) (3) Submit Your Solution

Advertisements

Read Solution (0) :

Please Login to Read Solution.

Previous Question: Two solid spheres A and B of equal volumes but of different densities dA and dB are connected by a string. They are fully immersed in a fluid of density dF. They get arranged into an equilibrium state as shown in the figure with a tension in the string. The arrangement is possible only if (A) dA < dF (B) dB > dF (C) dA > dF (D) dA + dB = 2dF Next Question: Which of the following statement(s) is/are correct? (A) If the electric field due to a point charge varies as r-2.5 instead of r-2, then the Gauss law will still be valid. (B) The Gauss law can be used to calculate the field distribution around an electric dipole (C) If the electric field between two point charges is zero somewhere, then the sign of the two charges is the same. (D) The work done by the external force in moving a unit positive charge from point A at potential VA to point B at potential VB is (VB - VA).

Login
Register

Sponsored Links

Advertisements

Challenger of the Day

no image

Dimple

India

Punjab

Time: 00:01:33

Points

19

Maths Quotes

The essence of mathematics is not to make simple things complicated, but to make complicated things simple.

S. Gudder

Don't learn Mathematics just to prove that you are not a mentaly simple person but learn it to prove that you are intelligent

Linda

Placed User Comments

M4Math helped me a lot.

Vipul Chavan 3 years ago

Thanks m4 maths for helping to get placed in several companies.
I must recommend this website for placement preparations.

yash mittal 4 years ago

2512K+Registerd user
1759K+Engineers
753K+MBA Asprirant
3K+Enginnering College
250+Company Exam
150K+Interview Questions

All rights are reserved to @m4maths.com