Latest IIT-JEE Aptitude Question SOLUTION: The rate of a reaction doubles when its temperature changes from 300 K to 310 K. Activation energy of such a reaction will be : (R = 8.314 JK–1 mol–1 and log 2 = 0.301) (1) 58.

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(#M40027835) IIT-JEE question 2011 question Keep an EYE

The rate of a reaction doubles when its temperature
changes from 300 K to 310 K. Activation energy of
such a reaction will be : (R = 8.314 JK–1 mol–1 and
log 2 = 0.301)
(1) 58.5 kJ mol–1 (2) 60.5 kJ mol–1
(3) 53.6 kJ mol–1 (4) 48.5 kJ mol–1

Asked In IIT-JEE MAN (11 years ago)

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