Latest IIT-JEE Aptitude Question SOLUTION: The Henry’s law constant for the solubility of N2 gas in water at 298 K is 1.0 × 10^5 atm. The mole fraction of N2 in air is 0.8. The number of moles of N2 from air dissolved in

• Placement Papers
• /
• IIT-JEE

IIT-JEE Question Papers:

(#M40028127) IIT-JEE question 2007 Question Keep an EYE

The Henry’s law constant for the solubility of N2 gas in water at 298 K is 1.0 × 10^5 atm. The mole fraction
of N2 in air is 0.8. The number of moles of N2 from air dissolved in 10 moles of water at 298 K and 5 atm
pressure is

Asked In IIT-JEE MAN (10 years ago)

Unsolved

Is this Puzzle helpful?   (0)   (5) Submit Your Solution