Latest IIT-JEE Aptitude Question SOLUTION: In a triangle ABC with fixed base BC, the vertex A moves such that cosB + cosC = 4 sin^2(A/2)..If a, b and c denote the lengths of the sides of the triangle opposite to the angles

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(#M40028141) IIT-JEE question 2008 Question Keep an EYE

In a triangle ABC with fixed base BC, the vertex A moves such that cosB + cosC = 4 sin^2(A/2)..If a, b and c
denote the lengths of the sides of the triangle opposite to the angles A, B and C, respectively, then
(A) b + c = 4a (B) b + c = 2a
(C) locus of point A is an ellipse (D) locus of point A is a pair of straight lines

Asked In IIT-JEE MAN (10 years ago)

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