Latest TCS Aptitude Question SOLUTION: In how many rearrangements of the word ERASED is the letter 'A' positioned in between the 2 'E's?

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(#M40028168) TCS Logical Reasoning question Keep an EYE

In how many rearrangements of the word ERASED is the letter 'A' positioned in between the 2 'E's?

Asked In TCS max (11 years ago)

Solved saurabh kumar Read Solution (27)

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Read Solution (27) :

ravi shankar rai  (11 years ago)

the word {eae} can take as a one wod now total will 4 word an they can arrange in
4! ways=24 ways

Is this solution Helpfull? Yes (60) | No (6)  

saurabh kumar  (11 years ago)

there is a group {eae}which can be arranged in 4 ways..and remaining words can be arranged in 3! ways . so our solution is..4*3!=24

Is this solution Helpfull? Yes (29) | No (10)  

shivangi  (11 years ago)

keep [EAE]together so
[eae]asr
so total arngment
4!/2!=12
2! for the repeated e's

Is this solution Helpfull? Yes (9) | No (11)  

kumar  (11 years ago)

I HAVE SEEN ALL THE ANS ,AND ALL OF THEM ARE DUMMY
FIRST THIN THAT THEY ARE ASKING FOR REARRANGEMENT NOT FOR ARRANGEMENT
therefore ans will be (arrangement - 1)

there are many approach to solve this question ,i am solving by one
soln: in all arrangement EAE will be eithere in
1)EEA
2)EAE
3)AEE
AND TOTAL ARRANGEMENT =6!/2!= (WAY OF ARRANGING 6 THING OUT OF WHICH 2 ARE ALIKE OF ONE KIND)

SO REQUIRED ARRANGEMENT (IN WHICH A BETWEEN TWO E,OUT OF THREE ONLY ONE )= 360/3=120
HENCE REARRAGEMENT WILL BE=120-1=119 (SINCE WE CANT TAKE ERASED ,HERE ALSO A BET 2 E'S)

Is this solution Helpfull? Yes (9) | No (14)  

sandeep gupta  (11 years ago)

if we keep EAE together and assume it as single entity then we will have 4 items to rearrange so ans is
4!=24

Is this solution Helpfull? Yes (6) | No (1)  

Olivia Pramanik  (11 years ago)

RSD(EEA)
here we treat the vowels as one letter.
no. of ways to arrange the letters=4!
3 vowels in which E occurs 2 times,so the vowels can be arranged in (3!/2!)=3 ways,which are(EEA),(EAE),(AEE).

So,one-third of all words will have 'A' in between the two 'E's.
So,total no of arrangements=(4!*(3!/2!))/3=24

Is this solution Helpfull? Yes (5) | No   

Damanjot Singh  (11 years ago)

the word ERASED has 6 characters in total.assuming EAE as a single word.
so now total characters =6-3+1=4 and these can be arranged in 4!ways and EAE can be arranged in 3! ways ..but EAE has two E's in it which can be arranged in 2! ways further. so the solution is 4!*3!/2!=72

Is this solution Helpfull? Yes (5) | No (2)  

arpit jain  (11 years ago)

it will be 4!*2 + 2!3! + 3!2! = 72

Is this solution Helpfull? Yes (4) | No (3)  

gaurav borra  (11 years ago)

Consider EAE as single elements.
then we have total 4 elements.
so total rearrangemrnt will be 4!=24

Is this solution Helpfull? Yes (4) | No   

VINEET  (11 years ago)

4! is the answer

Is this solution Helpfull? Yes (3) | No   

tejomay saha  (11 years ago)

4!/2! that should be the answer

Is this solution Helpfull? Yes (3) | No (1)  

Arindam Dhara  (11 years ago)

-A---- 4!
--A--- 2!3!
---A-- 3!2!
----A- 4!
total no of ways 24+12+12+24=96 ways

Is this solution Helpfull? Yes (2) | No (18)  

pratik namjoshi  (11 years ago)

24
take eae as one and remaining 3 total 4
4p4=24

Is this solution Helpfull? Yes (2) | No   

Saikat Guin  (11 years ago)

(EAE) can be placed in 4 places. ie. *RAD, R*AD, RA*D and RAD*. now RAD can be arranaged in 3! ways. so, the answer will be 4*3!= 24

Is this solution Helpfull? Yes (2) | No (1)  

sailakshmi  (10 years ago)

ERASED
E A E _ _ _
taking EAE as 1
1+3=4
no of ways of arranging=4!
total no of ways of arranging the word is=4! * 3!/2!=72

Is this solution Helpfull? Yes (2) | No (1)  

DHIREN  (11 years ago)

As it has been said between 2 E's 1 A should be there so the arrangement will be EAERSD,SO EAE one group which is fixed,i.e EAE=1 ,RSD can be arranged in 3 ways.(R is at=2nd,S at 3rd D at 4th place) .so it can be arranged in 4! ways(i.e 1 from EAE and 4 from rest,i.e 1*4=4! .so 4! factorial is 24
ANS=24

Is this solution Helpfull? Yes (1) | No (1)  

Payal  (11 years ago)

there will be rsd(eae) so it will be 4!=24

Is this solution Helpfull? Yes (1) | No   

puja kundu  (11 years ago)

EAERSD
suppose EAE as a single entity then number of letters are 4 so they can be arranged in 4! ways.now keeping A in between two E's this can be arranged in 2! ways so 4!*2!=48

Is this solution Helpfull? Yes (1) | No (1)  

Baljeet Singh  (11 years ago)

Make group [EAE], thus remaining 3 letters + this group, totals 4 words, which can be arranged in 4! ways. (24)

Is this solution Helpfull? Yes (1) | No (2)  

Guru Pranav  (11 years ago)

let eae be one words so total number of arrangements of four words can be done in 4! ways i.e, 24 ways :D

Is this solution Helpfull? Yes (1) | No (1)  

tarun kosta  (11 years ago)

EAERSD
In this word if we fix the fist three alphabets then remaining three can be arrange in 6 ways = 6
REAESD also 6 ways = 6 , similarly
RSEAED also = 6
RSDEAE also = 6
so there are total 24 rearrangements are possible.

Is this solution Helpfull? Yes | No   

Shashank Salaj  (11 years ago)

takin EAE as 1 alphabet and arranging the left outs, we can do it in 4!/2! ways. the 2! is bcoz of the two identical E's.

Is this solution Helpfull? Yes | No (3)  

Aditee pathak  (11 years ago)

eae act as a one word and remaining are 3 letters which we can arrenge them in3!=6 ways
and total we have 3+1=4 letters
so 6*4=24

Is this solution Helpfull? Yes | No   

bipin kumar  (11 years ago)

LET EAE as a one letter,remaining 3 letters are R,S,D......so we have to arrange these four letters according to question.....4 letters are their ..no.of ways of arrenging these four letters is 4!=4*3*2=24 ans

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Sk Inur Ali  (10 years ago)

ans is: 4!.......here take 'EAE' as one and there is another three...But that is why here A is placed in between two similar letter ,otherwise it will be 2!*4*.

Is this solution Helpfull? Yes | No (2)  

apoorva tewari  (10 years ago)

the word (eae) is treated as a single entity so, the total arrangements of rsd and eae is 4!*(3!/2!)=72

Is this solution Helpfull? Yes | No   

Pratik sharma  (10 years ago)

Ad we have to find Rearrangement thus

Rearrangement = Arrangement -1 ..(.because ERASED is already arrange)
thus 4!-1=23

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