Latest TCS Aptitude Question SOLUTION: A number when successively divided by 5, 3, 2 gives remainder 0, 2, 1 respectively in that order. What will be the remainder when the same number is divided successively by 2, 3,

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A number when successively divided by 5, 3, 2 gives remainder 0, 2, 1 respectively in that order. What will be the remainder when the same number is divided successively by 2, 3, 5 in that order

Asked In TCS (10 years ago)

Solved SOURAV BAKSHI Read Solution (14)

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SOURAV BAKSHI  (10 years ago)

2x+1
3*(2x+1)+2
5*[3*(2x+1)+2]
=30x+25
{30x+25}/2=15x+12(rem=1); [15x+12]/3=5x+4 (rem=0); (5x+4)/5=x (rem=4)
ans is 1,0,4

Is this solution Helpfull? Yes (94) | No (4)  

varun garg  (10 years ago)

this is the short trick which i am telling you .
it is applicable only on when the question say that find the remainder when order of divisibility is reversed.

write
5 0
3 2
2 1
leave the last 2, and multiply 1 by 3 then add 2 after this result will be multiplied by 5 and then add 0 so the remainder no. is 25
now divide 25 by 2 remainder will be 1 then by 3 rem. will be 0 and then by 5 finally rem. will be 4.
so 1,0,4 is the right answer.

Is this solution Helpfull? Yes (23) | No (5)  

Ajay Poshak  (10 years ago)

Let the number be 55
So 55%5 = 0 and 55/5 = 11 ; 11%3 = 2 and 11/3 = 3; 3%2 = 1
According to question,
55%2 = 1 and 55/2 = 27 ; 27%3 = 0 and 27/3 = 9; 9%5 = 4
So the remainder will be 1,0,4

Is this solution Helpfull? Yes (21) | No (8)  

sudheerkumar  (10 years ago)

answer is 1,2,0
the number is 5
if 5 is divided by 5 it ll gives rem zero
if 5 is divided by 3 it ll gives rem two
if 5 is divided by 2 it ll gives rem one
from the above the number 5 is satisfying the given condition
so that if 5 is divided successively with 2,3,5, than it ll gives 1,2,0

Is this solution Helpfull? Yes (7) | No (13)  

Mudassir Fazal  (10 years ago)

as number is divisible by 5 leving 0 and 3 leaving 2 and 2 leaving 1.
thus number can be written as
5(3(2m +1) +2)=original number
simplifying it
30m +25=original number.
thus deviding by 2 gives 1 leaving 15m+12
thus deviding by 3 gives 0 leaving 5m+4
thus deviding by 5 gives 4

Is this solution Helpfull? Yes (7) | No (1)  

manofmayhem  (10 years ago)

The no will be ((1*3)+2)5=25 (smallest possible no)

on successive division it will leave 1,0,4 as remainder

Is this solution Helpfull? Yes (5) | No (3)  

ankur  (10 years ago)

55 is correct answer... 100% sure

Is this solution Helpfull? Yes (3) | No (8)  

ratneshh  (10 years ago)

35 will be the no
and rem=1,2,0
chek out

Is this solution Helpfull? Yes (1) | No (5)  

Imran  (10 years ago)

n=5x+0
x=3y+2
z=2y+1
then if y=1 the no is div by 2 with rem 1 so that x=5 , n=25
25/2 rem =1, 12/3 rem=0, 4/5 rem=4
ans is 1,0, 4

Is this solution Helpfull? Yes (1) | No (1)  

DEEPANSHI SRIVASTAVA  (10 years ago)

given 5%x=0 ,3%a=3, 2%b=1

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murthy  (10 years ago)

THIS CAN BE SOLVED BY DOING THIS
First subtracting dividends by reminders respectively then we get
(5-0),(3-2),(2-1)
5,1,1
now LCM(5,1,1)=5
SO the required number is 5 (check with 5,3,2 we get reminders 0,2,1)
so 5 is successively divided by 2,3,5 we get the reminders 1,2,0 respectively.

Is this solution Helpfull? Yes | No (1)  

khushboo  (9 years ago)

5 3 2
0 2 1
first multiply 3 to 1 then add 1..after getting the result multiply with 5 and 0
i.e 3*1+2=5*5+0=25
then divide 25 by with 2, 3, 5 successively we get 1, 0, 4 as remainder
so ans is 1, 0, 4

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sivasankare k  (5 years ago)

1,0,2 . The num is 35

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Shweta Kumari  (5 years ago)

Can't say, don't know

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