Latest self Aptitude Question SOLUTION: no of zeroes at the end of the expression (2!)^2!+4!^4!+8!^8!+9!^9!+10!^10!+11!^11!

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(#M40028918) SELF question progression Keep an EYE

no of zeroes at the end of the expression (2!)^2!+4!^4!+8!^8!+9!^9!+10!^10!+11!^11!

(11 years ago)

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RAKESH  (11 years ago)

(2!)^2!+4!^4! will not contain any zero
8!^8! will contain 1*8! zeroes(since 8! will contain 1 zero so 8!^8! will contain 1*8! zeroes at the end of number)
similarly
9!^9! will contain 1*9! zeroes
10!^10! will contain 2*10! zeroes(10! contains 2 zeroes at the end of no. so 10!^10! will contain 2*10! zeroes at the end of the number)
similarly
11!^11! will contain 2*11! zeroes
total no. of zeroes at the end of expp will be = 8! + 9! + 2*10! + 2*11!

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Saloni Singh  (11 years ago)

did ny1 find a soln to dis qn???

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rajveer singh  (11 years ago)

exactly it's a right way of doing a question.

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Manish  (11 years ago)

check for the numbr of fives in the equation.

they are 5!+6!+7!+8!+9!+[2*(10!+11!)]
that shuld be the answer

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ratnesh  (11 years ago)

last two digit of 4!^4! is 76
and 2!^2!=4
76+4=80
only one zero at end of exp.

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