Latest Infosys Aptitude Question SOLUTION: Six persons A,B,C,D,E &F went to soldier cinema. There are six consecutive seats. A sits in the first seat followed by B, followed by C and so on. If A taken on of the six seats,

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(#M40000029) INFOSYS Logical Reasoning question Keep an EYE

Six persons A,B,C,D,E &F went to soldier cinema. There are six consecutive seats. A sits in the first seat followed by B, followed by C and so on. If A taken on of the six seats, then B should sit adjacent to A. C should sit adjacent to A or B. D should sit adjacent to A, B or C and so on. How many possibilities are there ?

Solution

First we have to arrange A, there is 1 method for it, for second person B, there are 2 methods one left and one right, for third 2 methods are there same as for B similarly for others, so total number of methods = 1*2*2*2*2*2 = 32

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Asked In Infosys (14 years ago)

Solved Read Solution (6)

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Read Solution (6) :

C.T.Narayanan  (14 years ago)

74 ( 3 * 24 + 2 )

Is this solution Helpfull? Yes (1) | No (13)  

Kushagra Krishna  (9 years ago)

According to me it will have innumerable possibilities because it all depends whether A sits on the corner seat or middle seat. If A sits on the corner then there will be only 2 ways for everyone to be seated but if A occupies one of the middle seats then there will be numerous ways in which B,C,D,E,F can be seated according to where A is sitting i.e. 2nd seat,3rd seat, 4th seat,5th seat because each of these persons are distinct. 32 is definitely not the answer.

Is this solution Helpfull? Yes (1) | No (4)  

maharaja  (9 years ago)

bt according to me....only 1 possible way.....because it is given that...a sits on 6th seat...so only person sits adjacent to it...???that is b then c....as follows...check out..

Is this solution Helpfull? Yes (1) | No (2)  

ANKUR  (9 years ago)

The answer should be 18.
1 case when is placed in between then there are 2 raise to the power 4 i.e 16 and
2 case is when A is at the starting or end i.e 2 . So total there are 18 ways in which the above arrangement is possible.

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pravin  (6 years ago)

32 by using formula

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amit ranjan  (6 years ago)

First we have to arrange A, there is 1 method for it, for second person B, there are 2 methods one left and one right, for third 2 methods are there same as for B similarly for others, so total number of methods = 1*2*2*2*2*2 = 32

Is this solution Helpfull? Yes | No   

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