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(#M40029931) TCS question Keep an EYE

1^1*2^2*3^3....48^48*49^49 calculate no. Of zeros

Asked In TCS Dipty Sharma (11 years ago)

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seetha  (11 years ago)

its 250 count number of 5's in 25 its (5*5) so (5^2)^25 gives 5^50 we usually miss there

Is this solution Helpfull? Yes (22) | No (2)  

RAKESH  (11 years ago)

count the no. of 5's in 1^1*2^2*3^3....48^48*49^49
5^5*10^10*15^15*20^20*25^25*30^30*35^35*40^40*45^45(only these terms consists 5)
=5^5*5^10*5^15*..............*5^45
so no. of 5's in 1^1*2^2*3^3....48^48*49^49=5+10+15+20+25+..........+45
=5(1+2+3+........+9)
=5*45=225
no. of zZEROES=225

Is this solution Helpfull? Yes (9) | No (17)  

Tarun Sharma  (11 years ago)

250 zeros

Is this solution Helpfull? Yes (5) | No (3)  

tarunima mukherjee  (11 years ago)

count the number of 5s. ans:250

Is this solution Helpfull? Yes (4) | No (3)  

Alok sahoo  (11 years ago)

ans is 100

Is this solution Helpfull? Yes (1) | No (6)  

dipu  (11 years ago)

rakesh kumar ache ladke ho , thora try kro or ye question galat die ho

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jit dhar  (11 years ago)

number of zero is 100. 10^10,20^20,30^30,40^40 total contain 100 zero.

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