Latest IBM Aptitude Question SOLUTION: Printer A prints 8192 character per min and printer B prints 13862 character per min four character are equal to one word. Printer A starts at 7:15 am while Printer B starts at 7:2

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Printer A prints 8192 character per min and printer B prints 13862 character per min four character are equal to one word. Printer A starts at 7:15 am while Printer B starts at 7:29 am then a twhat time both will have same no of words printed

Asked In IBM shubhi garg (11 years ago)

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Srijan Manish  (11 years ago)

at 20 seconds past 7:49 .... because 7.29-7.15 = 14 mints, so when B starts, A would have printed 8192 * 14 characters printed, i.e 114688 characters. Now, for B, the more number of characters it can print per minute is 13862 - 8192 = 5670 characters per minute. So, the time taken by printer B to cope up with printer A will be 114688/5670 minutes = 20.23 minutes ~ 20 minutes and a few seconds, so the time would be 7.29 + 20 minutes = 7.49 am. :)

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Alok Singh  (11 years ago)

may be solved as
let after x minutes of 7:29 they both be equal
13862*x=8192*(x+14)

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madanpal vishwakarma   (11 years ago)

here for printer A print 8192/4 =2048 word/min
printer B print 13862/4=3465+2char word/min
so the time difference 29-15=14min
lets assume that the time at which both have same char is n
so
2048*14+2048*n=3465*n+(2*n)/4

28672+2048n=3465n+(n/2)
57344+4096n=6930n+n
57344+4096n=6931n
6931n-4096n=57344
2831n=57344
n=2.2557
or n=20.3 approx

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Pragyan Baliarsingh  (9 years ago)

Rate*time=words
Ra=8192/4=2048 words/minute
Rb=13862/4= 3465.5 words/minute
7.29-7.15=14 mins
Ra.(T+14)=Rb.T
2048.(T+14)=3465.5*T
2048T +28672= 3465.5T
1417.5T =28672
T=20.22
Approximately 20 minutes, 14 seconds from 7:29 or 7:49:14 AM.

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