Latest TCS Aptitude Question SOLUTION: if n is the sum of two odd consecutive integers and less than 100 then find the maximum value of n

• Placement Papers
• /
• TCS

TCS Question Papers: TCS Interview Experience(90) TCS Company Profile

(#M40030112) TCS question number Keep an EYE

if n is the sum of two odd consecutive integers and less than 100 then find the maximum value of n

Asked In TCS PRIYA NAMDEO (10 years ago)

Unsolved Read Solution (8)

Is this Puzzle helpful?   (2)   (1) Submit Your Solution

Read Solution (8) :

bala hari krishna  (10 years ago)

47,49
47+49=96

Is this solution Helpfull? Yes (14) | No   

nikhil kumar pradhan  (10 years ago)

maximum it will be 100
so 50+50=100
taking that into consideration two closest cosequitive odds closer to 50 are 47 and 49......so 47+49=96

Is this solution Helpfull? Yes (3) | No   

sagar  (10 years ago)

47+49=96.................................

Is this solution Helpfull? Yes (1) | No   

megha borkar  (10 years ago)

let take the two odd numbers as 2n+1 and 2n-1(because even no is 2n so odd will be one after it or one before it).

sum=(2n+1)+(2n-1)=4n------ (1)
but according to question should be less than 100
100>4n
=>25>n
but n should be lesser than 25 b/c should be less than 100 so we can take the most suitable value 24.

put 24 in eqation (1)
(2*24+1)+(2*24-1)=96

so 96 is the ans...

Is this solution Helpfull? Yes (1) | No   

Sam  (10 years ago)

we have to find n1+n2=n
so let n1=43 and n2=47 then n1+n2=43+47

Is this solution Helpfull? Yes | No (1)  

Rajasekhar  (10 years ago)

43, 45
Let odd integers be x, x+2
x+(x+2)

Is this solution Helpfull? Yes | No (2)  

Manisha Choudhary  (10 years ago)

(2n+1)+(2n-1)< 100
4n

Is this solution Helpfull? Yes | No (2)  

sirisha  (10 years ago)

Two consecutive integers=(2n-1)(2n+1)
(2n-1+2n+1)

Is this solution Helpfull? Yes | No   

Please Login to Read Solution.