Latest m4maths Aptitude Question SOLUTION: A pencil cost Rs 0.25, a pen cost Rs 10 and a book cost Rs 25. How many each one should buy so that the total number of articles is 100 and the total amount is Rs. 1000?

40(pencils)*0.25=Rs.10
34(pens)*10=Rs.340,
26(books)*25=Rs.650,
total no of products=40=34=26=100//
total amount=10+340+650.

0.25*40+10*34+25*26=100 article and 1000 ammount...

40 pencil * .25 = 10
34 pen * 10 = 340
26 book * 25 = 650
Then 40+34+26=100 and 10+340+650=1000

x+y+z=100
0.25x+10y+25z=1000 =>
10x+10y+10z=1000 => 9.75x-15z=0 => 9.75x=15z =>x=1500z/975 =>x=20z/13
pencils=20,pens=67,books=13

There are three solutions.

Number of pencils = C Number of books = B Number of Pens = P

Total Number of articles = 100 = C + P + B
C = 100 – P - B -- equation 1

Total Purchase:

0.25 * C + 10 P + 25 * B = 1,000 , multiply by 4
C + 40 P + 100 B = 4,000 --- equation 2

From the above equations, we can infer that maximum value of P is 100, maximum value of B is 40 and Maximum value of C is 100. Minimum of any of them is 1. If the values are more than those maximum then equation 1 or 2 will not be satisfied.

As C + 40 P + 100 B = 4,000 , substitute value of C from equation 1
100 - P - B + 40 P + 100 B = 4,000
39 P + 99 B = 3900 divide by 39

P + (33/13) B = 100 -- equation 3

Here, 100 is an integer. P is an integer. So (33 B/13) is also an integer.
So B = 13, 26, or 39 only three possibilities.

1) B = 13, P + 33 = 100, P = 67
C = 100 - 13 - 67 = 20.
Total purchase = 20*0.25 +10*67 + 13*25 = Rs 1,000

2) B = 26, P + 33 * 26/13 = P + 66 = 100, P = 34
C = 100 - 26 - 34 = 40
Total purchase = 40*0.25+10*34+25*26 = Rs 1,000

3) B = 39 , P + 99 = 100, P = 1
C = 100 - 39 - 1 = 60
total purchase = 60*0.25 + 1 * 10 + 39 * 25 = Rs 1,000