Latest TCS Aptitude Question SOLUTION: in a circular table 6 men and 5 women are to be seated.find the number of ways of sitting arrangement such that no 2 women sit together?

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in a circular table 6 men and 5 women are to be seated.find the number of ways of sitting arrangement such that no 2 women sit together?

Asked In TCS Heena Jain (10 years ago)

Unsolved Read Solution (17)

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Read Solution (17) :

Prerak Jain  (10 years ago)

Ans:-5!*6c5*5!

No. of ways men can seat on circular table is (6-1)!
No. of potions for women is 6, so they can be seated in 6c5 ways and arrenge by 5!.

Is this solution Helpfull? Yes (40) | No (7)  

srinivas jestani  (10 years ago)

we arrange 6 men around the circular table in (6-1)! ways.There 6 places in between them.Now we arrange 5 women in these 6 places in 6P5 ways.so,5!*6P5 is the answer.

Is this solution Helpfull? Yes (15) | No   

Vinathi mullangi  (10 years ago)

first 6 men to be arranged in (6-1)!=5! ways
next in the 6 gaps 5 women is to be arranged in 6c5 ways
therefore 5!*6=720 ways

Is this solution Helpfull? Yes (5) | No (2)  

sravan  (10 years ago)

6 men +3 women + 1 bundle of 2 women = 10
(10-1)!*2!
answer =9!*2

Is this solution Helpfull? Yes (3) | No (6)  

Vipul Sharma  (10 years ago)

5!(ways for men to be in circular arrangment) * 6P5(ways to arrange women in the gaps)

Is this solution Helpfull? Yes (2) | No (1)  

Kuldeep  (10 years ago)

5!*(6C5 * 5!)
first arrange male then arrange females.

Is this solution Helpfull? Yes (2) | No   

navin  (10 years ago)

5!*6C5*5!.
6 men can be arranged in 5! ways..the spaces left b/w them are 6, so we can make 5 women sit in 6C5*5! ways

Is this solution Helpfull? Yes (2) | No   

amit kumar  (9 years ago)

6 men can be arranged around a table in (6-1)!=5! ways.

Now, if we place each woman between the men then no two women will be together. There are 6 available slots between the men, thus 6C5=6 is the number of ways we can choose 5 slots out of 6 for the women.

Next, these 5 women can be arranged in 5! ways, hence the total number of ways is 5!*6*5!=86,400.

Is this solution Helpfull? Yes (2) | No   

Jonnalagadda sambasivarao  (10 years ago)

6 men are arranged in fac(5) ways 6c5
ans=fact(5)*6c5

Is this solution Helpfull? Yes (1) | No (2)  

Amlan Mohanty  (10 years ago)

6!*5! is gona ne d answer

Is this solution Helpfull? Yes (1) | No (1)  

shahrukh  (9 years ago)

6 men can be arranged around a table in (6-1)!=5! ways.

Now, if we place each woman between the men then no two women will be together. There are 6 available slots between the men, thus 6C5=6 is the number of ways we can choose 5 slots out of 6 for the women.

Next, these 5 women can be arranged in 5! ways, hence the total number of ways is 5!*6*5!=86,400.

Answer: C.

Is this solution Helpfull? Yes (1) | No   

Shivangi Nagar  (10 years ago)

all-sitting together=not sitting together
(11-1)!-(7-1)!=6!*5039

Is this solution Helpfull? Yes | No (3)  

Vipul Sharma  (10 years ago)

here women will only have 5 option as the the arrangement are done in circle.
it would be 6C5 if there would be linear arrangement.

Is this solution Helpfull? Yes | No (1)  

Kuldeep  (10 years ago)

in circular manner (n-1)! arrangements and left positions are 6.
so ans will be= 4!*6!

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kavitha  (10 years ago)

men arrangement in circular table is(6-1)! ways
5women arranged in 6 places as 6p5
ans:6p5*5!

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neha jain  (10 years ago)

5!(54)4!9=1600

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sonali soni  (10 years ago)

How do i know which one is correct...!!!

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