Latest CAT Aptitude Question SOLUTION: 3 pumps, working 8 hours a day, can empty a tank in 2 days. How many hours a day must 4 pumps work to empty the tank in 1 day? A. 9 B. 10 C. 11 D. 12

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3 pumps, working 8 hours a day, can empty a tank in 2 days. How many hours a day must 4 pumps work to empty the tank in 1 day?

A.
9
B.
10
C.
11
D.
12

Asked In CAT jai Narayan Mishra (12 years ago)

Unsolved Read Solution (6)

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Read Solution (6) :

ANUJ MAURYA  (12 years ago)

3 pump 2 days 8 hrs
4 pump 2 days 8*3/4=6 hrs
4 pump 1 day 6*2=12 hrs

Is this solution Helpfull? Yes (20) | No (3)  

gunda varun  (12 years ago)

3 pumps working 8 hours a day for two days.
so the total working hours for 3 pumps together are 48 hours
if 4 pumps are working then they must each work for 12 hours (48*12=48)

Is this solution Helpfull? Yes (12) | No (3)  

Thakur dushyant pundir   (12 years ago)

in one hours empted part of tank by 3 pumps=1/16
in one hours empted part of tank by 1 pump=1/48
now in one hour empted part of tank by 4 pumps=1/12
it is implies that
1/12 part of tank empted in =1 hour
1 (1=whole part ) or tank will be empted in=(1*1)/(1/12)=12

answer==12 hours
D

Is this solution Helpfull? Yes (6) | No (1)  

harsh khatri  (8 years ago)

p1*h1*d1=p2*h2*d2;
3*8*2=h*4*1;
h=12 ans...

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nish  (12 years ago)

ans.D
3 pumps 8 hrs a day for 2 days working at rate r to complete wrk w.
3*8*r*2=w.....(1)
4 pumps x hrs a day for 1 day working at rate r completes wrk w.
4*r*x*1=w.....(2)
(1)/(2)
x=12

Is this solution Helpfull? Yes (2) | No (2)  

Arnav Banerji  (8 years ago)

simple ratio proportion question :
x hrs = 8 X 3/4 X 2/1

( in 3/4, 3 is in numerator as the no of pumps has decreased so hours taken will be less)
(in 2/1, 2 is in numerator and 1 is in denominator as no of day is increased so hours taken will be greater)

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