Latest Elitmus Aptitude Question SOLUTION: i have to numberd my house such that if it is a multiple of 3 than numberd (50 to 59) and if it not divisible by 4 than can numberd (60 to 69)........ Que.1- what can be my house

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(#M40030678) ELITMUS Numerical Ability question askd in elitmus 1st nov Keep an EYE

i have to numberd my house such that if it is a multiple of 3 than numberd (50 to 59) and if it not divisible by 4 than can numberd (60 to 69)........

Que.1- what can be my house number
(a)51 (b)63 (c)64 (d) All of the above

Asked In Elitmus gaurav kumar (10 years ago)

Solved RAKESH Read Solution (9)

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RAKESH  (10 years ago)

we have to 1st consider multiple of 3,if its not then apply 2nd condition not divisible by 4
51 is divisible by 3 but not by 4,satisfies both condition,cant be number twice
a)51 is multiple of 3 so must numbered betn 50 to 59(T)
b)63 is multiple of 3 so must numbered betn 50 to 59(F)
c)64 is not multiple of 3,but multiple of 4,so it cant be house number(F)
d)all of above(F)
ans(a)

Is this solution Helpfull? Yes (54) | No (1)  

RAKESH  (10 years ago)

go through options
since 51 is multiple of 3,not of 4 so house no. should within(50 to 59)
also 64 is divisible by 4 so lies betn (60 to 69),it contradicts given condns
option(a)

Is this solution Helpfull? Yes (15) | No (6)  

abhishek ganguly  (10 years ago)

51 means divisible by 3 and betwn(50-59)
63 means divisible by 3 but not betwn(50-59)
64 means divisible by 4 and given if NOT divisible by 4 then betwn(60-69)
so ans is 51

Is this solution Helpfull? Yes (6) | No   

Gaurav  (10 years ago)

b, it is because 63 does not lie between 50 and 59 and is multiple of 3 and also it is not divisible by 4.

Is this solution Helpfull? Yes (5) | No (7)  

rakesh  (10 years ago)

i think question has a little mistake,

Is this solution Helpfull? Yes (3) | No (1)  

Gaurav  (10 years ago)

51
since other options are not possible..

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sravani p  (10 years ago)

y it can't be option b..it is a multiple of 3 andi is not divisble by 4 ad is between (60 to 69) satsfyng ,2 nd condition?

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Aashish  (10 years ago)

ans: 51(a)
multiple of 3 and not divisible by 4

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ravi prakash  (10 years ago)

a will be ans
51 is divisible by 3
frt cnd apply.

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