Latest Elitmus Aptitude Question SOLUTION: a number is given with three bases base2,base 3,base5 such that last digit of the number in all the three cases is 1,and the leading digit is 1 in exactly 2 out of 3 cases.find th

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(#M40030784) ELITMUS Numerical Ability question Quant Keep an EYE

a number is given with three bases base2,base 3,base5 such that last digit of the number in all the three cases is 1,and the leading digit is 1 in exactly 2 out of 3 cases.find the number?

Asked In Elitmus abc (10 years ago)

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abc  (10 years ago)

91 is the right answr
1)31(base2)=11111
31(base3)=1011
31(base5)=111
2)91(base2)=1011011
91(base3)=10101
91(base)=331
condition is that last is 1 all bases and leading digit(first digit) is 1 in exactly 2 out of 3 cases.
31 has the leading digit 1 in all the cases .so 31 is wrong ( leading digit should be 1 in exactly 2 cases not more than that )

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satypal varma  (10 years ago)

divide 31 by 2 3 and 5 u will got both the condition satisfied.....and the another option is 91 divide by 5 you will got one 3.....so it is not satisfy the one condition........

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mansi  (10 years ago)

i think 31 is the answer

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