Latest Elitmus Aptitude Question SOLUTION: Q. HOW MANY 4 DIGIT NO.CAN BE MADE WITH THE DIGITS 1,2,3,4,5,6,7 DIVISIBLE BY 25 ONLY ONCE? Option a) 20 b) 24 c) 60 d) Cant be determined

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(#M40030865) ELITMUS Logical Reasoning question QUANTS Keep an EYE

Q. HOW MANY 4 DIGIT NO.CAN BE MADE WITH THE DIGITS 1,2,3,4,5,6,7 DIVISIBLE BY 25 ONLY ONCE?

Option
a) 20
b) 24
c) 60
d) Cant be determined

Asked In Elitmus sanjay singh (10 years ago)

Unsolved Read Solution (16)

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Read Solution (16) :

K.ARun  (10 years ago)

only the digits ending with 25 and 75 are divisible by 25.
So, 5 should occupy the one's place (1)
either 2 or 7 should occupy the 10's place. 2
from the remaining numbers 1236(2 or 7) occupy 100's place. 5
and then in thousand's place 4
so, 4*5*2*1=40;

Is this solution Helpfull? Yes (27) | No (21)  

RAKESH  (10 years ago)

DIVISIBLE BY 25 ONLY ONCE means?
some digits 3125,4375 are divisible by 25 twice
so 40 cant be answer
ans 24
(b)

Is this solution Helpfull? Yes (27) | No (12)  

RAKESH  (10 years ago)

DIGITS are 1,2,3,4,5,6,7
so no. is divisible by 25 only when last two digit is 25 or 75
DIVISIBLE BY 25 ONLY ONCE = TOTAL NO. DIVISIBLE BY 25 - NO. DIVISIBLE BY 625
=5*4*2*1-4*1
=40-4
=36

Is this solution Helpfull? Yes (9) | No (3)  

annepu pavani  (10 years ago)

nums divisible by 25 are 40 as we all know
nums divisible by 625 are:
----
units place is always 5----1 way
tens place can be 5,2,7..but 5 is already in units place..so it can be filled with 2 or 7 in---2 ways
hundreds place can be with 1,5,7..but 5 is already in units place..so it can be filled with 1 or 7 in---2 ways
thousands place in 4c1 ways..i.e 4 ways..
total 4*2*2=16
overall 40-16=24

Is this solution Helpfull? Yes (6) | No (1)  

pratibha   (10 years ago)

the ans would be 24(b). as the question says the num should be divisible by 25 only once that means it should not be divisible by 25*25 i.e. 625. so the ans will be obtained by( numbers div by 25- numb div by 625) i.e. 40-16=24

Is this solution Helpfull? Yes (5) | No (2)  

aditya sharma  (10 years ago)

to divide by 25 u must have 25,75 or 50 at right most side. so for right most position only one no. 5, for 10th position 2 or 7,100th-any of remaining 5 and 1000th only 4
so solution is 4*5*2*1=40

Is this solution Helpfull? Yes (4) | No (5)  

ashish makhija  (10 years ago)

its 20..
40-(the 4digit no. divisible by 75 ie.20)

Is this solution Helpfull? Yes (1) | No (2)  

jasna  (10 years ago)

from 40 we have to minus the numbers which is divisible by 625

Is this solution Helpfull? Yes (1) | No (1)  

jayant singh  (10 years ago)

_ _ 25- (1,3,4,6,7)-5P2=20
_ _ 75- (1,2,3,4,6)-5P2=20
TOTAL=40

Is this solution Helpfull? Yes (1) | No   

T.VIGNESWARA REDDY  (9 years ago)

it is divisible by only 25 but not with 625 and 15625 we observe that the first two places are not 5(4),6 and 25,75 so 3*4=12 again for 75 in last 3*4=12 24

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shubham  (10 years ago)

40...... i slove this question in Elitmus exam

Is this solution Helpfull? Yes | No (13)  

vertika srivastav  (10 years ago)

we have 00,25,50,75 as possibilities that if the no. end with these it is div by 25.but 0 is not there so we have 25 and 75 as probability so 5c1*4c1+5c1*4c1=40

Is this solution Helpfull? Yes | No (3)  

sekhar  (10 years ago)

it should not be 40 becoz only once we have to divide . from 40 we have to minus the numbers divisible by 75 and 125

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mahesh chandra  (10 years ago)

rakesh jee can u plz explain hw the ans is 24

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Sagar Gandhi  (10 years ago)

rakesh please explain your answer

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mahesh chandra  (10 years ago)

@rakesh
what about option a and d then?

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