Latest maths Aptitude Question SOLUTION: Q. What is the product of the irrational roots of the equation: (2x-1)(2x-3)(2x-5)(2x-7)=9? Option (a) 3/2 (b) 4 (c) 3 (d) 3/4

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(#M40030875) MATHS Numerical Ability question Keep an EYE

Q. What is the product of the irrational roots of the equation:
(2x-1)(2x-3)(2x-5)(2x-7)=9?

Option
(a) 3/2
(b) 4
(c) 3
(d) 3/4

Asked In maths RAKESH (10 years ago)

Solved GayathriRaju Read Solution (2)

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GayathriRaju  (10 years ago) Best Solution

(2x - 1) (2x - 3) (2x - 5) (2x - 7) = 9
Let 2x - 4 = y
=> (y + 3) (y + 1) (y - 1) (y - 3) = 9
=> (y^2 - 1) (y^2 - 9) = 9
=> y^4 - 10y^2 + 9 = 9
=> y^2 (y^2 - 10) = 0
=> y = 0 or ± √(10)
=> 2x - 4 = ± √(10)
=> x = (1/2) [4 ± √(10)]
=> product of the irrational roots
= (1/2)^2 * [4 + √(10)] [4 - √(10)]
= (1/4) * 6
= 3/2.
so,the answer is 3/2.......

Is this solution Helpfull? Yes (8) | No (3)  

Divya   (10 years ago)

How cum its (1/2)^2 in the 11th statement..I think it must be
=>(1/2)*[4+sq(10)][4-sq(10)]
=>(1/2)*[16-10]
=>6/2
=>3

Is this solution Helpfull? Yes (3) | No (4)  

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