Latest IBM Aptitude Question SOLUTION: Q. A, B, C, D, E and F are six positive integers such that B + C + D + E = 4A C + F = 3A C + D + E = 2F F = 2D E + F = 2C + 1 If A is a prime number between 12 and 20, then 1. The

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Q. A, B, C, D, E and F are six positive integers such that
B + C + D + E = 4A
C + F = 3A
C + D + E = 2F
F = 2D
E + F = 2C + 1
If A is a prime number between 12 and 20, then

1. The value of F is
(A) 14
(B) 16
(C) 20
(D) 24
(E) 28

2. Which of the following must be true?
(A) D is the lowest integer and D = 14
(B) C is the greatest integer and C = 23
(C) B is the lowest integer and B = 12
(D) F is the greatest integer and F = 24
(E) A is the lowest integer and A = 13

Asked In IBM SOURAJYOTI BASU (10 years ago)

Unsolved Read Solution (2)

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Read Solution (2) :

devendra kumar  (10 years ago)

0 down vote


B + C + D + E = 4A ------1

C + F = 3A ----------------2

C + D + E = 2F -----------3

F = 2D --------------------4

E + F = 2C + 1-----------5

Also A can 13,17 or 19

Eliminating D from all the equations we get

B+2F = 4A ------6

C+F = 3A -------7

C+E = 3F/2 -----8

E+F = 2C+1 ----9

Adding 7 and 8

2C+E+F = 3(A+F/2)

4C+1 = 3(A+F/2)

Substituting value of C from 7

4(3A - F) + 1 = 3(A+F/2)

=> A = (11F - 2)/18 => Only for A = 17, F is an integer

Therefore A = 17, F = 28, C = 23 , D = 14, B = 12, E = 19

1.) F = 28

2.) B = 12 and the lowest

Is this solution Helpfull? Yes (25) | No (2)  

ANKITA SINHA  (10 years ago)

1. Solve through options..it would be easy and would take less time. Thus,answer is (E)28.

Is this solution Helpfull? Yes (5) | No (3)  

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