Latest Elitmus Aptitude Question SOLUTION: Q. Find the largest 4 digit number which when divided by 10,15,22 leaving the reamainders 4,6,10 respectively

• Placement Papers
• /
• Elitmus
• /
• Numerical Ability
• /
• LCM and HCF

Elitmus Question Papers:

(#M40031095) ELITMUS Numerical Ability question quant Keep an EYE

Q. Find the largest 4 digit number which when divided by 10,15,22 leaving the reamainders 4,6,10 respectively

Asked In Elitmus ravi (10 years ago)

Unsolved Read Solution (14)

Is this Puzzle helpful?   (7)   (3) Submit Your Solution LCM and HCF

Read Solution (14) :

Himanshu upadhyay  (10 years ago)

@VIKAS
we have to find a largest 4 digit no say abcd such that on dividing this no by 10,15,22 we get remainder of 4,9,10
and in options middle two no were given
like 95,65,67 etc...
so now we know in no abcd bc could be one of the above...
now apply hit and trail
to be divisible by 10 and leaving remainder 4, the last no must be 4
so check for divisibility by 15,22 where last no is certainly 4,and pick each option
let say i have picked 95 as middle two no.
i knw last no would be 4,
so i have a954
no of choices for a 1,9 as it can't be zero.
i got my answer when i put 9 in place of a. and it was largest as it's two starting digits were 99 as per given in options.hope u understood now..

Is this solution Helpfull? Yes (9) | No (5)  

Harisudan sen  (9 years ago)

Question:-find the largest 4 digit number which when divided by 10,15,22 leaving the reamainders 4,9,10respectively.

step 1:- let the no. is N
1 N=22*a+10
2 N=15*b+9
3 N=10*c+4
now in equation 1 put value of a form 0,1,2,3,4....
and we get 10,32,54,76..

step 2:-now the series divide by 10 and 15 respectively as we want reminder as 6
and 4.Now we can see When we divide 54 by 10&15 we get 6 & 4 as reminder.

step3:-general equation is N=(lcm of numbers)*p+54
so N=330*p+54 assume the no. for that we can reach near by questions need
let p=30 so we get N=9900+54=9954 that is the answer.

Is this solution Helpfull? Yes (9) | No (1)  

Himanshu upadhyay  (10 years ago)

9954 when divided by 10,15,22 gives remainder of 4,9,10
question is wrong it was leaving remainder of 4,9,10 and the options were
middle two no are
a) 88 b)95 c)64

Is this solution Helpfull? Yes (7) | No   

NITHISH  (8 years ago)

Sorry to say that the above question is stated wrongly but the correct (or) actual question is
find the greatest 4 digit number which when divided by 10,11,15,22 leaves 3,4,8,15 as remainder respectively.

a)9907
b)9903
c)9893
d)none
as none is one of the answer choices, therefore i believe to be on the safer side we must solve it instead of working on the answer choices...!!!

the difference between the divisors and their corresponding remainders is constant and is equal to 7; 10-3=11-7=15-8=22-15=7; also the LCM of the divisors 10,11,15,22=330;

now the largest four digit number is 9999; when we divide 9999 with 330 remainder is 99; therefore largest number that will divide 10,11,15,22=9900 hence our desired answer is 9900-7=9893

Is this solution Helpfull? Yes (4) | No (1)  

Shubham Raj  (8 years ago)

ans - 9954
let take ' N ' is four digit no
(let a,b,c are quotient)
so , forming equation , N =10a + 4 --> 4,14,24,34,44,54,64 (lets take a=0,1,2,3,4,5,6,-,-,----
N =15b + 9 ------> 9,24,39,54,69
and N =22c + 10 -------> 10,32.54,76
common term is = 54 (from eqn of all three N)
general form of N = Lcm (of all dividend no ) * Y + common no
N = Lcm(10,15,22) * y + 54
=> N = 330y + 54
now again use hit and trial method for y (for forming four digit no)
take y=30
therefore N = 330*30 +54 =9954 (abcd)

Is this solution Helpfull? Yes (3) | No   

vikash kumar  (10 years ago)

@ Himanshu & Ravi..can u plz tell d way for solve this question....at here or badshahmit@gmail.com

Is this solution Helpfull? Yes (2) | No   

ravi  (10 years ago)

its wrong questn.question was
find the largest 4 digit number which when divided by 10,15,22 leaving the reamainders 4,9,10respectively

Is this solution Helpfull? Yes (1) | No   

Chandu  (10 years ago)

when we divided the largest 4 digit number with 10,15,22 it gives the reamainders 4,9,10.. so the largest 4 digit number is 9954..

Is this solution Helpfull? Yes (1) | No   

Arnab Halder  (10 years ago)

@Ravi 1*22 = 22 now 22 + 10 = 32
32 * 15 = 480 ; 480+ 9 = 489
489 * 10 = 4890 ; 4890 + 4 = 4894
so the number is 4894 ........

Is this solution Helpfull? Yes (1) | No   

vishal singh thapa  (10 years ago)

can not determined.

Is this solution Helpfull? Yes | No (2)  

Trisha   (10 years ago)

Options were given for this question? Then the solutions becomes easy @ravi

Is this solution Helpfull? Yes | No   

PRATIM JANA  (8 years ago)

wrong question...leaving the reamainders 4,9,10 respectively not 4,6,10

Is this solution Helpfull? Yes | No   

Lakhi kant Roy  (8 years ago)

i think question is wrong,
The reminder should be 4,9 and 10 respectively,and if reminder is 4,9 and 10 then our ans will be-->9954

Is this solution Helpfull? Yes | No   

jaideep sharma  (6 years ago)

9990 is the answer
first minus the values of remainder from their respective divisors
so these are 4,9,10
after that take lcm of these no.s
LCM 90
largest 4-digit no is 9999
9999/90 and it leaves 9 as a remainder
so that number is 9999-9=9990

Is this solution Helpfull? Yes | No   

Please Login to Read Solution.