Latest Infosys Aptitude Question SOLUTION: Q. Uncle Reuben and Aunt Cynthia came to town for shopping. Reuben bought a suit and hat for $15. Cynthia paid as much as for her hat as Reuben did for his suit then she spent the

• Placement Papers
• /
• Infosys
• /
• Logical Reasoning
• /
• Blood Relations

Infosys Question Papers: Infosys Interview Experience(10) INFOSYS Company Profile

(#M40031158) INFOSYS Logical Reasoning question reasoning Keep an EYE

Q. Uncle Reuben and Aunt Cynthia came to town for shopping. Reuben bought a suit and hat for $15. Cynthia paid as much as for her hat as Reuben did for his suit then she spent the rest of their money for a new dress. On the way home Cynthia called Reuben's attention to the fact that his hat cost $1 more than her dress, then she added, if we had divided our hat money differently so that we bought different hats mine costing 1 and 1/2 time cost of yours then we each would have spent the same amount of money. In that case Uncle Reuben asked "how much would my hat have cost"

Asked In Infosys suresh (11 years ago)

Unsolved Read Solution (5)

Is this Puzzle helpful?   (11)   (5) Submit Your Solution Blood Relations

Read Solution (5) :

Ishpreet Kaur  (11 years ago)

Let us use R for Reuban, C for Cynthia, H for Hat, S for Suit, and D for Dress.

For Reuban, Cost of hat and Suit sums upto 15
R(h) + R(S) = 15-----(1)

Further, Cost of Cynthia's Hat = Cost of Reubena's Suit
C(h) = R(S)-------------(2)

Given, Cost of Cynthia's hat is 1 and 1/2 times that of Reubann's hat
C(h) = 3/2 R(h)-----------(3)

From (2) and (3) we get, R(S)= 3/2 R(S)-----(4)

Substitute R(S) in (1) we get,

R(h) + 3/2 R(h) = 15

5/2 R(h) = 15

R(h) = 2/5 * 15

R(h) = 6

Therefore, Cost of Uncle Reuben's Hat is $6.

Is this solution Helpfull? Yes (66) | No (3)  

sharath kumar reddy  (11 years ago)

reuben (suit+hat)=15
reuben suit=cynthia hat
reuben hat=1+cynthia dress
trial and error method 9+6=15
rs=9
rh=6
cd=5
total money=9+9+6+5=29

Is this solution Helpfull? Yes (5) | No (2)  

ashok kumar busi  (11 years ago)

r.hat+r.suit=15
c.hat=r.suit
c.hat=c.dress+1
c.hat is 1 and 1/2 more than r.hat
so,c.hat=3/2*r.hat
since c.hat =r.suit
therefore r.hat+(3/2*r.hat)=15
so, r.hat=6, c.hat=9, c.dress=8,r.hat=9
here r=reuben, c=cynthia

Is this solution Helpfull? Yes (3) | No   

ashok kumar busi  (11 years ago)

in the above r.hat =c.dress+1
c.dress=5.
sorry for the mistake.

Is this solution Helpfull? Yes (2) | No   

vikash kumar  (11 years ago)

Ans is 2
Let us use r for Reuban, c for Cynthia, h for Hat, s for Suit, and d for Dress.
1st case:-
r(h)+r(s)=15
c(h)=r(s) => r(h)=15-c(h)
$ c(h)=c(d)+1 => c(d)=c(h)-1=15-r(h)-1
=> c(d)=14-r(h).....(1)
2nd Case:-
if, c(H)=3/2 r(h)....(2)
{"c(H)" for different Hat.old one was "c(h)"}
den, c(H)+c(d)=15 => 3/2r(h)+14-r(h)=15 ...(from 1&2)
=> r(h)=2
CHEK UR ANS AS:- case 1:-
for R: 2+13=15
for C: 13+12=25
case 2:-
new c(h)=3/2.2=3
s0,
for R: 2+13=15
3+12=15
If any one thinks dis is ri8 solution den plz like

Is this solution Helpfull? Yes (1) | No (8)  

Please Login to Read Solution.