Latest IBM Aptitude Question SOLUTION: What is the next number of the following sequences 1) 5, 1, 2, 8, 8, 1, 0, 9, 9, 2, 3,.... 2) 5, 1, 2, 8, 1, 0, 9, 2, 3, 14, 1, 3,.... 3) 6, 3, 3, 9, 12, 5, 7, 35, 8, 6, 2,....

• Placement Papers
• /
• IBM
• /
• Numerical Ability
• /
• Sequence and Series

IBM Question Papers: IBM Interview Experience(49) IBM Company Profile

(#M40031182) IBM Numerical Ability question number series Keep an EYE

What is the next number of the following sequences

1) 5, 1, 2, 8, 8, 1, 0, 9, 9, 2, 3,....

2) 5, 1, 2, 8, 1, 0, 9, 2, 3, 14, 1, 3,....

3) 6, 3, 3, 9, 12, 5, 7, 35, 8, 6, 2,....

4) 24, 42, 1/2, 2, 65, 56, 1 1/5, 5/6, 73, 37,....

5) 4, 2, 5, 9, 5, 11, 13, 7, 16, 17, 9,.....

6) 8, 16, 3, 27, 4, 8, 7, 19, 2, 0, 7,.....

Asked In IBM Madhurya KR (11 years ago)

Unsolved Read Solution (12)

Is this Puzzle helpful?   (9)   (3) Submit Your Solution Sequence and Series

Read Solution (12) :

RAKESH  (11 years ago)

1)5, 1, 2, 8, 8, 1, 0, 9, 9, 2, 3, X
(5, 1, 2,8), (8, 1, 0, 9), (9, 2, 3,X)
5+1+2=8
8+1+0=9
9+2+3=x=14

2) 5, 1, 2, 8, 1, 0, 9, 2, 3, 14, 1, 3
5+1+2=8,8+1+0=9,9+2+3=14,14+1+3=18

3) 6, 3, 3, 9, 12, 5, 7, 35, 8, 6, 2
(6,3,3,9),(12,5,7,35),(8,6,2,X)
(3+3,3,3,3*3),(5+7,5,7,5*7),(6+2,6,2,6*2)
X=12

4) 24, 42, 1/2, 2, 65, 56, 1 1/5, 5/6, 73, 37
24, 42, 1/2, 2, 65, 56, 6/5, 5/6, 73, 37
(24,42),(1/2,2),(65,56),(6/5,5/6),(73,37),(x,y)
cosider 1st no. of each group
(24,1/2),(65,6/5),(73,x)
(24,2/4),(65,6/5),(73,7/3)
so x=7/3 y=3/7
or x=2 1/3 y=3/7

5) 4, 2, 5, 9, 5, 11, 13, 7, 16, 17, 9
(4,2,5),(9,5,11),(13,7,16),(17,9,x)
third group is sum of 1st & 2nd
4+9=13
2+5=7
5+11=16
4th group is sum of 1st & 3rd
4+13=17
2+7=9
5+16=x=21
so x=21
6) 8, 16, 3, 27, 4, 8, 7, 19, 2, 0, 7 ,x
(8,16,3,27),(4,8,7,19),(2,0,7,x)
8+16+3=27
4+8+7=19
2+0+7=9=x
or x=9

Is this solution Helpfull? Yes (41) | No   

manimalika konduru  (11 years ago)

5+1+2=8
8+1+0=9
9+2+3=14

Is this solution Helpfull? Yes (3) | No   

Rajeswari  (11 years ago)

5+1+2=8
8+1+0=9
9+2+3=14
14+1+3=18

Is this solution Helpfull? Yes (2) | No   

manimalika konduru  (11 years ago)

3) 6,3,3,9,12,5,7,35,8,6,2
(6,3,3,9) (12,5,7,35) (8,6,2,?)
3+3=6,3*3=9
7+5=12,7*5=35
6+2=8,6*2=12

Is this solution Helpfull? Yes (2) | No   

Madhavi Mokkapati  (11 years ago)

1) 5+1+2=8
8+1+0=9
9+2+3=14

Is this solution Helpfull? Yes (1) | No   

manimalika konduru  (11 years ago)

6)8,16,3,27,4,8,7,19,2,0,7
8+16+3=27
4+8+7=19
2+0+7=9

Is this solution Helpfull? Yes (1) | No   

jassmeet  (11 years ago)

First make group of three
(4,2,5) (9,5,11) (13,7,16) (17,9,x)
Now,
In 1st Group: 5-4=1
In 2nd Group: 11-9=2
In 3rd Group: 16-13=3
Similarly,In 4th Group: x-17=4 ; x=21 Ans

Is this solution Helpfull? Yes (1) | No   

Rajeswari  (11 years ago)

By multiplying 2nd & 3rd digit we get 4th digit,
6,3*3=9 ie 6,3,3,9
12,5*7=35 ie 12,5,7,35
8,6*2=12 ie 8,6,2,12
Is this right??

Is this solution Helpfull? Yes | No   

Madhavi Mokkapati  (11 years ago)

5)
(4,2,5)
(9,5,11)
(13,7,16)
(17,9,x)
Take row diff
1st column- 5,4,4
2nd column- 3,2,2
3rd column- 6,5,(x-16)
x-16 = 5
x=21

Is this solution Helpfull? Yes | No   

Manasa Tippireddy  (11 years ago)

24 reverse 42 , 1/2 reverse 2
65 reverse 56 , 1 1/5=6/5 reverse 5/6
73 reverse 37 , next is 7/3 or 2 1/3

Is this solution Helpfull? Yes | No   

shivee  (11 years ago)

4) 24, 42, 1/2, 2, 65, 56, 1 1/5, 5/6, 73, 37

24=42 take two digit of 24 and 42 ie 24
2/4=1/2
1/2=2

65=56 agn take two digit ie 65
6/5
65=56

73=37
7/3
so d next nu is 37

Is this solution Helpfull? Yes | No   

BABILU KB  (11 years ago)

4) 24,42,1/2,2,65,56,1 1/5 ,5/6,73,37,?
first no=24
2nd no= reverse of 1st no= 42
3rd no= divide the digits in the 1st no(24) 2/4=1/2
4th no =divide the digits in 2nd no(42) 4/2=2
similarly ..
next no=65
reverse of 65 =56
divide the digits in the 1st no(65)=6/5 ,not that we can write 6/5 as 1 1/5 ( (1*5+1)/5 ) .so the next no is 1 1/5
divide the digits in 56=5/6

similarly
1st no= 73,
reverse of 73=37
divide the digits in 73=7/3, so the next no wil be 7/3 or 2 1/3

Is this solution Helpfull? Yes | No   

Please Login to Read Solution.