Latest elitmus Aptitude Question SOLUTION: Q. How many 1's present in the binary form of number 519*1024+11*64+3

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Q. How many 1's present in the binary form of number 519*1024+11*64+3

Asked In elitmus nagireddy (11 years ago)

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Vijay Pratap Singh  (11 years ago)

Easiest way to do this type of questions:
519*1024+11*64+3 = (2^9+2^2+2^1+2^0)*(2^10)+(2^3+2^1+2^0)*(2^5)+(2^1+2^0) = 2^19+2^12+2^11+2^10+2^8+2^6+2^5+2^1+2^0
number of 2^something = number of 1's = 9 (answer)

Is this solution Helpfull? Yes (14) | No (3)  

nagireddy  (11 years ago)

9 1's are present

Is this solution Helpfull? Yes (7) | No (4)  

Chandni Maurya  (11 years ago)

ans=9 1's
519*1024+11*64+3
lets start with multiplication,
519*1024 =1000000111*10000000000 (binary multiplication)= 10000001110000000000
1.e 1000000111 followed by 10 zeros

11*64=1011 * 1000000 = 1011000000 (total 10 digit)
at last
3=11
(it is clear here no need of further addition)
total 1's = 4+3+2 =9

Is this solution Helpfull? Yes (6) | No   

jagadeesh kumar.B  (11 years ago)

1000000111+10000000000+1011+1000000+11= eleven(11) ones(1) are present... so option is 11
(Hint: divide the numbers with 2)

Is this solution Helpfull? Yes (5) | No (7)  

Paras  (11 years ago)

10 1's are there

Is this solution Helpfull? Yes (3) | No (2)  

ravi  (11 years ago)

9 times "1"

Is this solution Helpfull? Yes (2) | No (1)  

ravi  (11 years ago)

options were 1)9 2)10 3)12 4)none of these.
there was no 11 there.
and we have to find the number of 1's in the number we get by adding all these.

Is this solution Helpfull? Yes (2) | No (1)  

anujnandwana  (11 years ago)

there are 9 ones

Is this solution Helpfull? Yes (2) | No (1)  

senaritra Das  (11 years ago)

11 one's present.1st see in 512 ,one 1 is their,and(512+7)in 7 three 1 are their.so in 519 ,4 ones are their and in 1024 one 1 is present.and operation of 519 and 1024 gives 5 ones...like this u hav to do..

Is this solution Helpfull? Yes (1) | No (4)  

Arnab Halder  (11 years ago)

519*1024+11*64+3 = 532136 ( by solving )
then convert into binary by dividing 2... u will get binary number which consists 9 '1'.... so ans is 9.... sure..... just do it....

Is this solution Helpfull? Yes (1) | No   

Vijay Singh Adhikari  (11 years ago)

519*1024+11*64+3 can be written as=
(2^9+2^2+2^1+2^0)2^10+(2^3+2^1+2^0)2^6+2^1+2^0
=2^19+2^12+2^11+2^10+2^9+2^7+2^6+2^2+2^0

= 9 times 1
hence there are 9 1's

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shashank Rawat  (10 years ago)

10 ones will the answer just find binary of 532163..

Is this solution Helpfull? Yes (1) | No (2)  

N Arun Singh  (11 years ago)

options were 9,10,11 none of the above ..
none !!

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Paras  (11 years ago)

option are 8,9,10,none

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N Arun Singh  (11 years ago)

nagireddy ,paras ..how did u get 9? ...the mul resultsin 532163 takin it t binay u"l get more 1"s

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N Arun Singh  (11 years ago)

@paras are u sure about the options were 8,9,10 and none

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Shubham Saxena  (11 years ago)

answer is 9 yr , no more discussion!!
warna 2.5 kilo ka hath mu p padega!! :P

Is this solution Helpfull? Yes | No (1)  

RAJSHREE PATNAIK  (11 years ago)

value is 82163.so bianary value is 1011101100111.SO,9 1's are present.

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PRATIM JANA  (9 years ago)

11 1's present

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JUGAL KHAJURIYA  (9 years ago)

519*1024+11*64+3=605891
605891 binary is 10010011111011000011
ie 11 1's present

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Vikash kumar  (8 years ago)

CORRECT ANSWER =11

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