Latest TCS Aptitude Question SOLUTION: There are certain diamonds in a shop. 1 thief stole half of diamonds and 2 more. 2 thief stole half of remaining and 2 more 3. same as above 4 same as above. 5 came nothing was lef

• Placement Papers
• /
• TCS
• /
• Logical Reasoning
• /
• General Mental Ability

TCS Question Papers: TCS Interview Experience(91) TCS Company Profile

(#M40031326) TCS Logical Reasoning question Keep an EYE

There are certain diamonds in a shop.
1 thief stole half of diamonds and 2 more.
2 thief stole half of remaining and 2 more
3. same as above
4 same as above.
5 came nothing was left for that.
how many diamonds was there?

Asked In TCS chandreyee chowdhury (11 years ago)

Unsolved Read Solution (12)

Is this Puzzle helpful?   (10)   (4) Submit Your Solution General Mental Ability

Read Solution (12) :

swethakottakota  (11 years ago)

answer=60
let the total diamonds x.
first person took x/2 and extra 2,
so the remaining are (x/2)-2= let it be y,
similarly , the second person took y/2 + 2, so remaining are y/2 -2.........
after 4 similar attempts,the shop is left with 0 diamonds,
so the final expression will be
1/2*(1/2*(1/2*(x/2 -2)-2)-2)-2 =0
from this x =60
so, first person took 60/2 +2 =32
2nd person took 28/2 +2 = 16
3rd person took 12/2 +2 =8
4th person took 4/2 +2 =4
so........we are left with 0 diamonds in the shop.. i think this the correct answer.

Is this solution Helpfull? Yes (34) | No (1)  

kannika  (11 years ago)

answer=60
solution:
let the total diamonds be x.
diamonds stole by 1st thief =x/2+2=(x+4)/2;
n by 2nd one=(x+4)/4;
by 3rd one=(x+4)/8;
by 4th one=(x+4)/16;
Hence x-[(x+4/2)+(x+4/4)+(x+4/8)+(x+4/16)]=0;
On solving, x=60

Is this solution Helpfull? Yes (9) | No (1)  

sivaraman  (11 years ago)

last person=0
fourth person=4 diamonds
third person=12 diamonds
second person=28 diamonds
first person=60 diamonds

Is this solution Helpfull? Yes (4) | No (2)  

bhawna  (10 years ago)

in such type of question we solve it in a backward order
the last person was left with 0 diamonds so the 4th thief had divided the diamonds such that only 2 diamonds were left only then he will take 2 more diamonds.
that means - 2*2 =4

Now for the 4th thief- 4 diamonds were there
So previously there were
4+2=6 diamonds after dividing it by half.
So, the 3rd thief had 6*2=12 diamonds

Similarly, 2nd thief saw (12+2) * 2 = 28 diamonds

And 1st thief saw (28+2) * 2 =60 diamonds (ANS)

Is this solution Helpfull? Yes (2) | No   

Manikumar R  (11 years ago)

60 diamonds was there....

Is this solution Helpfull? Yes (1) | No (1)  

chinatamani chinna reddeppa  (11 years ago)

by using options it can solve easily so 60

Is this solution Helpfull? Yes (1) | No   

pritam banerjee  (10 years ago)

best soltutn will be try to go for options and clculatate it will sav elots of tym

Is this solution Helpfull? Yes (1) | No   

Snehashish Pal  (11 years ago)

there are 140 diamonds

Is this solution Helpfull? Yes | No (8)  

Ujjwal Mandal  (11 years ago)

60 diamonds

Is this solution Helpfull? Yes | No (1)  

Devi Nallamilli  (11 years ago)

answer is 60

Is this solution Helpfull? Yes | No   

Chams  (10 years ago)

let us consider,there was x diamonds
after 1st one: x-(x/2-2)
2nd:(x-x/2-2)-(x/4-2)
3rd:((x-x/2-2)-(x/4-2))-(x/8-2))
4th: ((x-x/2-2)-(x/4-2))-(x/8-2))-(x/16-2)
finally there is no diamonds
so (16x-8x-4x-x)/16=8

therefore x=128

ans:128

Is this solution Helpfull? Yes | No (7)  

Swathi  (10 years ago)

ans:-is 120
each person gets half of diamonds plus 2 more in each round
{[(x/2)+2]+[(x/4)+2]+[(x/8)+2]+[(x/16)+2]}=x
x=128
but i have not subtracted each time 2 more diamonds in half of reaming diamonds so 4*2=8
128-8=120
Total diamonds are 120

Is this solution Helpfull? Yes | No (6)  

Please Login to Read Solution.