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Self Question Papers:

(#M40031478) SELF Numerical Ability question Number series Keep an EYE

Find the missing term denoted by ?

2,11,31,73,?

Avishek Pattanaik (11 years ago)

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RAKESH  (11 years ago)

2=1^3+1=1^3+1!
11=3^2+2=3^2+2!
31=5^2+6=5^2+3!
73=7^2+24=7^2+4!
series is of form (n^2+m!) where n=1,3,5,7,9(series of odd no.)
& m=1,2,3,4,5 (series of natural no.)
so next no. is
9^2+5!=81+120=201
ans 201

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RAKESH  (11 years ago)

2=1^2+1=1^2+1!
11=3^2+2=3^2+2!
31=5^2+6=5^2+3!
73=7^2+24=7^2+4!
series is of form (n^2+m!) where n=1,3,5,7,9(series of odd no.)
& m=1,2,3,4,5 (series of natural no.)
so next no. is
9^2+5!=81+120=201
ans 201

Is this solution Helpfull? Yes (2) | No   

julee verma  (11 years ago)

2*2+7=11
11*2+9=31
31*2+11=73
73*2+13=159

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mahima srivastava  (11 years ago)

difference of consecutive numbers
11-2=9
31-11=20
73-31=42
now calculate difference of differences
20-9=11
42-20=12
so, 42+13=55
now 55+73=128
so ans is 128
orignal series:- 2 .... 11... 31... 73..... 128
difference series:- 9.....20....42....55
difference series2:- 11....12...13

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