Latest CAT Aptitude Question SOLUTION: The monthly salary of a person was Rs 320 for each of the first 3 years. He next got annual increment of Rs 40 per month for each of the following successive 12 years.His salary r

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The monthly salary of a person was Rs 320 for each of the first 3 years. He next got annual increment of Rs 40 per month for each of the following successive 12 years.His salary remained stationary till retirement when he found that his average monthly salary during his service period was Rs 694. Find the period of his service?
a > 25
b> 15
c> 40
d> 50

Asked In CAT Ankit Boae (10 years ago)

Unsolved Read Solution (4)

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amaravenkatesh ranga  (9 years ago)

total salary for first 3years=3*12*320=11520
rs 40 per month increment for each of following 12 consecutive years.
for 4th year monthly salary=rs 360
for 5th year monthly salary= rs 400
.
.
.
.
for 15th year monthly salary = 360+(12-1)40= rs 800
his total salary for these 12 years = 12*12/2*(360*2+(12-1)*40)
= rs 83520
His monthly salary till retirement = rs 800
let,no.of years he worked with this salary = x

his average salary = (11520+83520+(800*12*x))/((3+12+x)*12)
= 694(given)
by solving this x= 23.49
total service period = 23.49+12+3 =38.49>25
so answer is a

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bhavana wali  (10 years ago)

total salary for first 3 years where monthly salary is rs 320=320x12x3=11520
total salary for 12 years with increment of 40=320+40=360x12x12=51840
average given=694
(51840-11520)/x=694
x=40320/694=58 years
answer=d

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MD SOHAIL AKHTER  (10 years ago)

salary he got in 3 yrs= 320*36=11520
after increment of rs.40 per month, salary he got for 12 yrs= 360*144=51840
avg salary he got till retirement= 694
the no. of year he worked= (51840-11520)/694= 58 years

so the ans is (d)

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Ankita kumbhare  (9 years ago)

SoIutlon The monthly salary for the first 3 years (i.e .. 36 months) = Rs 320
. The monthly salary in the 4th year = Rs 360
The monthly salary in .the 11thyear .. Ra 400
The monthly salary in the 6th year = Ra 440
The monthly salary in the Il1th year - [320 + 40(12») = Rs 800
Now, as per the given problem,
. .. [3(320) +!! [2(360) +(12 -1)40] + n(800)]_
the average salary (3 + 12 + n) - Ra 698
=
( 7920 + 800n) = 698
15+n·
n = 25
:. The total service = (3 + 12 + 25) = 40 years.

http://books.google.co.in/books?id=sO6mFHUuuVwC&pg=PA96&lpg=PA96&dq=the+monthly+salary+of+a+person+was+rs+320+for+each+of+the+first+three+years&source=bl&ots=jvYRhLwnuB&sig=Q8V_yu112Jkl90peZaxzOaO-tNI&hl=en&sa=X&ei=tuFUVJfnD8iQuQTyj4LwAQ&redir_esc=y#v=onepage&q=the%20monthly%20salary%20of%20a%20person%20was%20rs%20320%20for%20each%20of%20the%20first%20three%20years&f=false
please ref page no 96

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