Latest IBM Aptitude Question SOLUTION: Q. What is the next number of the following sequences 1)0.8,1.8,3.6,3.6,4.6,9.2,9.2,10.2,? 2)11,8,17,14,23,24,31,32,? 3)(15*4+3)/4,16,26,(9*5+1)/5,9,19,(64*3+2)/3,65,75,(30*8+3)

1)0.8,1.8,3.6,3.6,4.6,9.2,9.2,10.2,?
(0.8,1.8,3.6),(3.6,4.6,9.2),(9.2,10.2,X)
0.8+1=1.8, 1.8*2=3.6
3.6+1=4.6, 4.6*2=9.2
9.2+1=10.2, 10.2*2=X => x=20.4

2)11,8,17,14,23,24,31,32,X
count prime no.s from 11
11,13,17,19,23,29,31,37,41,43
11,8,17,14,23,24,31,32,X,Y
series is of formed(alternate prime n0.-5)
so X=41, Y=43-5=38

3)(15*4+3)/4,16,26,(9*5+1)/5,9,19,(64*3+2)/3,65,75,(30*8+3)/8,X,Y
(15+ 3/4 ,16,26),(9+ 1/5 ,9,19),(64 +2/3 ,65,75),(80 +3/8 , x,y)
in every group,
2nd term= approaximation of 1st no.
3rd term= 2nd no.+10

SO X=approax(80 +3/8)=80
Y=X+10=80+10=90

4)3,2,1,4,5,4,5,1,0,6,3,?
(3,2,1),(4,5,4),(5,1,0),(6,3,X)
in every group 1st term is increasing by +1
& (3rd term-2nd term=1)
s0 3-X=1 => x=2

5)7.2,2.2,,3.2,16,11,12,60,55,56,?
(7.2,2.2,,3.2),(16,11,12),(60,55,56),x
7.2-2.2=5,2.2+1=3.2,3.2*5=16
16-11=5,11+1=12, 12*5=60
60-55=5,55+1=56,56*5=280 => x=280

6)3,5,2,100,4,7,3,196,1,6,5,?
(3,5,2,100),(4,7,3,196),(1,6,5,x)
100=(3+5+2)^2
196=(4+7+3)^2
x=(1+6+5)^2 => 144

7)2,9,5,49,11,169,x
prime no.s 2,3,5,7,11,13,17
2,3^2,5,7^2,11,13^2,x => x=17

8)2,6,5,14,11,26,17,?
prime n0.s 2,3,5,7,11,13,17,19
2,3*2,5,7*2,11,13*2,17,x => x=19*2=38

9)22,19.5,21.45,33,26,15,-1,x,y
(22,33,-1),(19.5,26,x),(21.45,15,y)----- its not clear


10) 1/4,1/4,1/2,3/2,6,?
1/4, (1/4*1),(1/4*2),(1/2*3),(3/2*4),(6*5=x) => x=30

11) 9,4,16,6,36,21,441
(9,4),(16,6),(36,21),(441,X)
9=4+5*1
16=6+5*2
36=21+5*3
441=x+5*4 => x=441-20=421

12)9,12,4,8,12,15,5,9,3,6,2,6,6,9,X,Y

(9,12,4,8)(12,15,5,9)(3,6,2,6)(6,9,X,Y)
9+3=12,12/3=4,4+4=8
12+3=15,15/3=5,5+4=9
3+3=6,6/3=2,2+4=7

so 6+3=9, 9/3=X, X+4=Y => X=3, Y=7

correction for 3rd qn

3)(15*4+3)/4,16,26,(9*5+1)/5,9,19,(64*3+2)/3,65,75,(30*8+3)/8,X,Y
(15+ 3/4 ,16,26),(9+ 1/5 ,9,19),(64 +2/3 ,65,75),(30 +3/8 , x,y)
in every group,
2nd term= approaximation of 1st no.
3rd term= 2nd no.+10

SO X=approax(30 +3/8)=30
Y=X+10=30+10=40

1. 0.8
0.8 +1=1.8
1.8*2=3.6
3.6+1=4.6
4.6*2=9.2
9.2+1=10.2
10.2*2=20.4

12.9,4,16,6,36,21,441,?
9-4=5
16-6=10
36-21=15
similarly
441-421=20
ans 421

6) 3+5+2=10, 10^2=100
4+7+3=14, 14^2=196
1+6+5=12, 12^2=144
ans 144

If 45.65

( 22, 19.5, 21.45), (33, 30.5, 33.55),( 44, 41.5 , x)

first terms of brackets => 22 , 33 , 44
second terms of brackets => 19.5 , 19.5 + 11 , (19.5 + 11*2)
third terms of brackets => 21.45 , (21.45 + 12.1) , (21.45 + 2*12.1)

=> x = 21.45 + 2 * 12.1 = 45.65

correction in 9th series 22,19.5,21.45,33, 30.5, 33.55,44, 41.5 ,?
and the solution is
divide it into 3 sets
( 22, 19.5, 21.45), (33, 30.5, 33.55),( 44, 41.5 , x)

first terms of brackets => 22 , 33 , 44
second terms of brackets => 19.5 , 19.5 + 11 , (30.5 + 11*2)
third terms of brackets => 21.45 , (21.45 + 12.1) , (33.55 + 12.1)

=> x = 33.55+ 12.1 = 45.65(ans)

2)11,8,17,14,23,24,31,32,?
11-3=8
8+9=17
17-3=14
14+9=23
and
23+1=24
24+7=31
31+1=32
32+7=41(ans)

Dear RAKESH

kindly give clarity on the 11 question pls...

7) series is of prime numbers
2,(3^2),5,(7^2),11,(13^2),17,(19^2)

1)20.4
2)39
3)30
4)
5)280
6)144
7)17
8)54
9)
10)30
11)3
12)421

2) 41
8) 38

Description:
2) alternative prime series and missing alernate terms...
11,(13),17,(19),23,(29),31,(37),41
Note: 39 is not a prime number(3*13=39).
So answer is 41.

8)This is also related to prime number series.
But in this the alternate prime number is replaced by (prime number * 2)
2,(3*2=6),5,(7*2=14),11,(13*2=26),17,(19*2=38)
So answer is 38...
Do u agree guys???

3)divide it into 4 sets
{9,12,4,8){12,15,5,9,),(3,6,2,6),(6,9,?}
see 9+3=12
12/3=4
4+4=8
12+3=15
15/3=5
5+4=9
6+3=9
9/3=3(ans)

ans 30 mixed fraction 15 3/4 =63/4=15.75~16
9 1/5 =46/5 = 9.2 ~ 9
64 2/3 =194/3=64.6 ~ 65
30 3/8 =243/8 =30.3 ~ 30
for next series 10 should be added

5)
7.2,2.2,3.2,16,11,12,60,55,56
3.2*5=16
12*5=60
56*5=280 ans

sorry that is 11 question

12)9,4,16,6,36,21,441,?
(9,4),(16,6),(36,21),(441,?)
9-4=5*1
16-6=5*2
36-21=5*3
441-?=5*4
441-20=421
ans=421