Latest IBM Aptitude Question SOLUTION: A mans age is 125% of what it was 10 years ago, but 83 1/3 % of what it will be after ten 10 years. What is his present age? A. 70 B. 60 C. 50 D. 40

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(#M40032550) IBM Numerical Ability question IBM QUESTION Keep an EYE

A mans age is 125% of what it was 10 years ago, but 83 1/3 % of what it will be after ten 10 years. What is his present age?

A. 70

B. 60

C. 50

D. 40

Asked In IBM anindita panda (10 years ago)

Unsolved Read Solution (14)

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Read Solution (14) :

raju thammineni  (10 years ago)

175-94=81
188-124=64
372-323=49
1292-?=36

Is this solution Helpfull? Yes (32) | No (1)  

Prasann Modi  (10 years ago)

175-94=81=9^2
188-124=64=8^2
372-323=49=7^2
1292-1256=36=6^2
Ans=1256.

Is this solution Helpfull? Yes (13) | No (1)  

Nitin itare  (8 years ago)

ans is op c. 50
let the age be x. so
(x-10)*(125/100) = (x-10)*(250/300) [solve 83 1/3% = 250/300]
x= 50.

Is this solution Helpfull? Yes (9) | No   

vishakha saini  (8 years ago)

Let the age before 10 years = x

Then 125x/100 = x + 10

=>125x = 100x + 1000

=> x = 1000/25 = 40



Present age = x + 10 = 40 +10 = 50

Is this solution Helpfull? Yes (8) | No   

RAKESH KUMAR SINGH  (10 years ago)

94*2=188
124*3=372
323*4=1292
similarly

Is this solution Helpfull? Yes (4) | No (5)  

Niharika Vardhan  (8 years ago)

Let present age be x
x = 125% of (x-10)
x = 83 1/3 % of (x+10)
=> x = 50
C. 50

Is this solution Helpfull? Yes (4) | No (2)  

mahima tiwari  (10 years ago)

175-9^2=94*2=188
188-8^2=124*3=372
372-7^2=323*4=1292
1292-6^2=1256*5=6280

Is this solution Helpfull? Yes (3) | No (3)  

mridul  (10 years ago)

1.) 175-94=81 (9^2) follow this pattern now
94*2=188
2.) 188-124=64 (8^2)
124*3=372
3.) 372-323=49 (7^2)
323*4=1292
4.) here.. wat must be substracted frm 1292 to get the next number in the series. look at the pattern
1292- 36 (6^2)=1256
1256 is the next number

Is this solution Helpfull? Yes (3) | No (3)  

SUDHIR SHARMA  (10 years ago)

1292 and 6280 will be the next two terms
because 175-81=94
then 94*2=188
again 188-64=124
then 124*3=372
again 372-49=323
then 323*3=1292

Is this solution Helpfull? Yes (1) | No (2)  

uthra murugesan  (8 years ago)

see this for this answer
http://www.careerbless.com/aptitude/qa/ages1.php

Is this solution Helpfull? Yes (1) | No   

divya  (8 years ago)

let present age=x
10yrs ago age is 125% of (x-10)
after 10yrs age is 83 1/3(250/3%) of (x+10)
125/100(x-10)=250/300(x+10)
5/4[(x-10)]=/6[(x+10)]
6x-60=4x+40
2x=100
x=50

Is this solution Helpfull? Yes (1) | No   

pravesh kumar  (8 years ago)

C. ans 50
...

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Karthika  (8 years ago)

ans is 50
125% (x-10)=83 1/3% (x+10)

Is this solution Helpfull? Yes | No   

skk  (7 years ago)

(125/100)*(x-10)=((250/3)/100)*(x+10)

250/3 means=83 1/3

x=50

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