Latest Infosys Aptitude Question SOLUTION: Q. Sum of all 120 numbers formed by using 1, 2, 3, 3, 3, and 4 is? Options 1) 35555516 2) 35555520 3) 45555516 4) 34555606 5) 45555520 6) 45555506 7) 34562816 8) 48355520 9) 48355

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(#M40032607) INFOSYS Numerical Ability question combination permutation Keep an EYE

Q. Sum of all 120 numbers formed by using 1, 2, 3, 3, 3, and 4 is?
Options
1) 35555516
2) 35555520
3) 45555516
4) 34555606
5) 45555520
6) 45555506
7) 34562816
8) 48355520
9) 48355516
10) None of these

Asked In Infosys (10 years ago)

Solved RAKESH Read Solution (7)

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Read Solution (7) :

RAKESH  (10 years ago)

total no. = 6!/3!=120
in which 20 no.s starting with 1,2 & 4 each,total 60
& there will be 3*20=60 no. starting with 3

sum=111111*(20*1+20*2+60*3+20*4)=35555520

Is this solution Helpfull? Yes (40) | No (2)  

Richi Sharma  (10 years ago)

total no. = 6!/3!=120
now we have to check now many time a digit is repeated. as there are 6 digits we do 120/6=20
that means every digit is repeated 20 times except digit 3 which is repeated 3*20=60 times.

sum=(sum of the digits at the unit place)*(111111)
= (20*1+20*2+60*3+20*4)*111111=35555520

Is this solution Helpfull? Yes (28) | No   

Gaurav Dhar Dwivedi  (10 years ago)

RAKESH,can u tll me y u hv taken 60*3 in the solution.

Is this solution Helpfull? Yes (3) | No (2)  

SONU GUPTA  (10 years ago)

20*16(100000+10000+1000+100+10+1)=111111*320=35555520

Is this solution Helpfull? Yes (2) | No (1)  

RAKESH  (10 years ago)

111111*(20*1+20*2+60*3+20*4)
=35555520

Is this solution Helpfull? Yes (1) | No (4)  

Ashok  (10 years ago)

2) 35555520

Is this solution Helpfull? Yes | No (2)  

tarek ali  (9 years ago)

None of the above
right answer is 111*(20*1+20*2+20*4+60*3)=35520

Is this solution Helpfull? Yes | No (3)  

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