Latest Infosys Aptitude Question SOLUTION: USA+USSR=PEACE then P+E+A+C+E=?

U S A
(+)U S S R
---------------
P E A C E If each of the alphabets represent an unique digit,
--------------- and the front digit is not zero, find their values..
Soln:


NOTE: the max carry tat can be produced by adding two single digit nos is 1
• The value of P is obviously 1..
•The value of E is 0(9+1=10) and 1 goes as carry..
•considering the one's column(A+R=E),as E is 0,A+R must be 10 and the carry s forwarded to ten's column..
•now trial n error and backtracking starts..
•lets try in order from one's column.. A+R=10..lets try in numerical order..since 1 is in use,lemme assume A=2 and obviously R=8..
•and let me go on with my assumption in ten's column too,and try with S=3(as 1,2 r in use)..
•this gives 1+3+3=7.and C becomes 7 form our assumption..
•continuing in 100's column,U(9)+S(3)=>12..which shows and carry=1 ,A=2.this coincides with our assuption..
•in 1000's column,1+U(9)=10,showing E=0 and P=1 ,shows our assumptions ars perfect..
9 3 2
+ 9 3 3 8
-------------------
1 0 2 7 0
-------------------

can any one explain it clearlyy

please check with my solution
9447+943=10390
it is also match with this problem..can any one tell me??? for this type of problem may possible 2 different answer.

usa=>932
ussr=>9338
peace=>10270
p+e+a+c+e=10

how to solve this kind of sums...can any1help me

how to solve cryptarithmetic??

USA ===> 938
+USSR ===> 9332
-------===> ------
PEACE ===> 10270
-------- -------

USSR
+USA
PEACE
P=1,E=0,U=9,A=2,C=7,R=8,S=3
1+0+2+7+0=10

932+9338=10270

943+9442=10385

sry. it's wrong

cryptarithmatic is all about practicing...practice makes man perfect!!!!!!
here...
E=0,P=1,A=2,S=3,C=7,R=8,U=9
USA=932
USSR=9338
PEACE=10270
1+0+2+7+0=10

10270 is the right answer.10390 can't be the answer because both C and U cannot have the same value.

. U S A
(+)U S S R
---------------
P E A C E
---------------
considering that every alphabet represents a unique no.(0-9 obviously)

P=1 (only possible carry generated)
E => generated carry => U of USSR must have a carry on it (1)
=> U + (1) >= 10 but U A + R = 10
U + S results in A
=> S + 9 = 1A =10 + A
from above two equations we get
S + R = 11
A + R = 10
=> S = A + 1
and as A + R = 10
possible values of A/R are 2/8, 3/7, 4/6, 6/4, 7/3, 8/2
for S : 3,4 (because c=2s, so 5 is a no go)also S>=5 generates carry which changes our equation to
S+U+(1) = 1A => S+10 = 1A=>>> A=S which is not possible

so the right answers are:

A=2,S=3 => PEACE = 10270
A=3,S=4 => PEACE = 10390


9 3 2
+ 9 3 3 8
-------------------
1 0 2 7 0
-------------------