Latest Infosys Aptitude Question SOLUTION: IF AFTER+TWO=YEARS THEN WHAT IS THE VALUE OF Y+E+A+R+S IS?

4 9 7 0 3
- - 7 2 8
----------
5 0 4 3 1

If u notice the question then u'll get that "F = E" it means the value of 'F' is changed to 'E' and it is possible when the previous iteration carry 1.
but in the next iteration, value of 'A' is also changed to 'Y' it means the previous iteration i.e 'F' carry 1, and the previous iteration have only one alphabet i.e 'F' and its carry 1 then the value of 'F = 9' and whatever value will come from previous iteration i.e 'T + T' must carry 1 then it will satisfy the values "F=9,E=0"now put these value in the respective alphabet.

now check the last column i.e "R+O=S" also check the next column too i.e "E+W=R" and u know the value of 'E=0' from here u have to find 'W=R' and if u notice then u will identify that the value if 'W' is changed to 'R' it means its carry 1 from its previous iteration i.e "R+O=S" then the value of 'S' must be greater than 10 then it will carry 1.
now check what are the possible value will give more than 10 and remember 9 and 0 already assign to F and E respectively. So '8+2=10' is not possible,
'8+3=11' it is possible and it carry 1 then assign the value of "R=3,O=8 and S=1"
now check 'E+W=R' u have "E=0,R=3" from here u will get the value of 'W=2'.

Now check "T+T=A" no matter whatever value of 'A' will come.u have to remember that 'T+T=A' must carry 1.
if u put '5+5=10' i.e '0' not possible 'E=0' already assign,
'6+6=12' i.e '2' not possible 'W=2' already assign,
'7+7=14' i.e '4' it is possible.
then take the value of "T=7,A=4 and Y=5"

therefore the answer is Y+E+A+R+S=13

Y + E + A + R + S = 13

after = 2 9 6 0 8
+ two = 6 7 3
---------------------------
years = 3 0 2 8 1

how
AFTER= 49703
and TWO = 728
Kindly explain

49703
+728
_________
50431

sum=13

TWO = 746
AFTER=29705
YEARS=30451

Y+E+A+R+S = 13

how to solve these type of questions?