Latest TCS Aptitude Question SOLUTION: If x = 3 + 1 and y = 3 - 1 , then the value of (x2 + y2) is: 3 - 1 3 + 1

• Placement Papers
• /
• TCS
• /
• Numerical Ability
• /
• Age Problem

TCS Question Papers: TCS Interview Experience(90) TCS Company Profile

(#M40032668) TCS Numerical Ability question numeric Keep an EYE

If x = 3 + 1 and y = 3 - 1 , then the value of (x2 + y2) is:
3 - 1 3 + 1

Asked In TCS rohan (10 years ago)

Solved SUNNY KUMAR SHAW Read Solution (9)

Is this Puzzle helpful?   (11)   (6) Submit Your Solution Age Problem