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(#M40032766) ELITMUS Numerical Ability question Ratio and Proportion Keep an EYE

A can contains a mixture of two liquids A and B in proportion 7:5. When 9 litres of mixture was drawn off and the can was filled with B, the proportion of A and B becomes 1:2. How many litres of mixture was contained by the can initially?

Asked In Elitmus Ankit Boae (10 years ago)

Unsolved Read Solution (6)

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mohan lal garg  (10 years ago)

let initially mixer=x
A=7x/12 and b=5x/12
and 9 liter drown

A=7(x-9)/12 b=5(x-9)/12
filled with b
b=5(x-9)/12+9
A=7(x-9)/12

now ratio of A and B is 1:2
means b=2A
5(x-9)/12+9=2*7(x-9)/12
9=9(x-9)/12
x=21

ans=21 liter mixer
thank you

Is this solution Helpfull? Yes (43) | No (3)  

Nidhi  (10 years ago)

Let a:b=7:5 =7x:5x (let assume x)
then total 12x
if 9 litre of mixture is drown off then same then remaining parts of a and b in the mixture
a= 7x-7x*9/12x =7x-21/4 and thus b also 5x-15/4
now 9 liters of b is added then the amount of b became (7x-15/4)+9
now the ratio of a and b is given as 1:2
so 7x-21/4:(7x-15/4)+9=1:2
after solving value of x is 7/4
so the total amount of mixture initially was 12x= 12*7/4= 21 liters
ans. 21 liters .

Is this solution Helpfull? Yes (6) | No   

bujji  (10 years ago)

(7x-9)/(5x+9)=1/2
by solving x=3

so can intially contains 7x+3x=21+15=36

Is this solution Helpfull? Yes (2) | No (5)  

Simran  (10 years ago)

Suppose the can initially contains 7x and 5x of mixtures A and B respectively.

Quantity of A in mixture left = 7x - 7 x 9 litres = 7x - 21 litres.
12 4
Quantity of B in mixture left = 5x - 5 x 9 litres = 5x - 15 litres.
12 4

7x - 21
4
= 7
5x - 15 + 9
4
9
28x - 21 = 7
20x + 21 9
252x - 189 = 140x + 147

112x = 336

x = 3.

So, the can contained 21 litres of A.

Is this solution Helpfull? Yes (2) | No (1)  

Vicky singh  (10 years ago)

48 liters was contained initially in the can....

Is this solution Helpfull? Yes (1) | No (4)  

priyanka kumari  (10 years ago)

ans is = 21 litres

Is this solution Helpfull? Yes | No   

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