Latest Others Aptitude Question SOLUTION: How many different arrangements can be made by using all the letters of the word "INDEPENDENCE" if (i)D's come together? (ii)D's do not come together?

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(#M40003278) OTHERS question Permutation and Combinations Keep an EYE

How many different arrangements can be made by using all the letters of the word "INDEPENDENCE" if
(i)D's come together?
(ii)D's do not come together?

Asked In Others PREETHI (12 years ago)

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Aman Sharma  (5 years ago)

There are 3N, 4E, 2D, 1I, 1P and 1C in the word independence.
Total arrangements of word INDEPENDENCE =12!/3!*4!*2! = 1663200
Solution of D's come together : So take two D's together as one D
Total arrangements = 11!/3!*4! (Since total words with d taken together is 11 and since there are 3 N's and 4 E's together) = 277200
Solution of D's don't come together : total arrangements - arrangements of D being together = 1663200-277200 = 1386000

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