Latest Elitmus Aptitude Question SOLUTION: A contractor undertook to complete a piece of work in 120 Days and employed 140 men upon it. At the end of 66 days only half of the work was done,so he put on 25 extra men. By how

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(#M40032981) ELITMUS Numerical Ability question Time and work Keep an EYE

A contractor undertook to complete a piece of work in 120 Days and employed 140 men upon it. At the end of 66 days only half of the work was done,so he put on 25 extra men. By how much time did he exceed the specific time?

Asked In Elitmus Ankit Boae (10 years ago)

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rahul jain  (10 years ago)

half of the work is done by 140 persons in 66 day .
now remaining half work will be done by 165 persons in x days

66*140 = 165*x
x = 56
so the remaining half work will be done in 56 days .
so the total elapsed time to complete the work = 66+56 = 122
so the time exceed by 2 days.

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Sudeep Sahu  (10 years ago)

2 Days

Since, work done by 140 men in 66 days = 140M*60D => 9240 M-D (M-D => men days)
(which is half work done)
days left = 120-66 => 54
work left = 9240 M-D (as it is half work done. So, to complete the work we
need to do this much again)
But, in 54 days work done by 140 + 25(extra men)= 165M*54D => 8910M-D
work left after working remaining 54 days with 165 men =9240-8910 => 330M-D

Now,
we have 165 men to do 330M-D work
Days required to complete this work = 330/165 => 2 days
Ans. 2 days more required.

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Gaurav Dobriyal  (9 years ago)

total Work=(no. of person * no. of days)=(half work in 66 days)
therefore, complete work = 2*66*140=18480, out of which 9240 days are left
Now, no. of persons =140+25= 165
Req days= days left/no. of person= 9240/165 = 56 days
=> it takes 66+56= 122 days to complete the work
But 120 days are given
=> 2 days are exceeded

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kundan prasad  (9 years ago)

Ans: 2 days
Sol: formula is (M*D*H)/W=Constant............(where M=man,D=day,H=hour and W=work)
according given question
(66*140)/(1/2)=(D*165)/(1/2)
D=56

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kundan kumar singh  (8 years ago)

work done=total number of person*number of days;
half of work done=140*66;
for half of remaining work 25 extra men are added.
therefore ,total men for half work remaining=140+25=165;
let 2nd of work will be completed in X days;
140*66=165*X
X=122;
122-120=2days

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Anuj kumar  (6 years ago)

TOTAL MAN-DAYS REQUIRED TO COMPLETE THE REMAINING WORK = 140 * 66 = 9240 MAN-DAYS
NOW 25 MORE MEN ARE EMPLOYED.
TOTAL MEN = 165
165 * DAYS = 9240
DAYS = 56 DAYS
TOTAL TIME TAKEN TO COMPLETE THE WORK = 66 +56 = 122 DAYS
TIME EXCEEDED = 122-120 = 2 DAYS

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harshraj harsh  (2 years ago)

M1*D1= M2 * D2
1/2. 1/2


WHERE .

140*66 = 165*X

X = 56 DAYS

66+56 = 122 DAYS

122-120 =

2 ( EXCEED DAYS )

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