Latest Elitmus Aptitude Question SOLUTION: In what time would a cistern be filled by three pipes whose diameter are 1 cm , 4/3cm, 2 cm running together.. when the largest alone will fill it in 61 minutes; the amount of wate

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(#M40033034) ELITMUS Numerical Ability question Pipes and Cistern Keep an EYE

In what time would a cistern be filled by three pipes whose diameter are 1 cm , 4/3cm, 2 cm running together.. when the largest alone will fill it in 61 minutes; the amount of water flowing in by each pipe being proportional to the square of its diameter?

Asked In Elitmus Ankit Boae (10 years ago)

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Vivek Jain  (10 years ago)

ans 36 min;
(4k+16/9k+1*k)T=C..........(1)
k:some pipe const same for all
C:capacity of cistern
T:required time
also 4k*61min=C........(2)
substituting (2)in (1), we get
T=36min

Is this solution Helpfull? Yes (23) | No (3)  

Simran  (10 years ago)

For all three pipes together:
2^2 = 4
1^2 = 1
4/3^2 = 16/9

4 + 1 + 16/9 = 61/9 is proportional to the amount of water flowing in.

We know that for the largest pipe: 2^2 = 4 is proportional to the amount of water flowing in and this takes 61 minutes.
so,
61 x (4/(61/9)) = 61 x (36/61) = 36 minutes.

Is this solution Helpfull? Yes (11) | No   

sravani  (9 years ago)

2cm diameter is largest-------61mins
larger the diameter lesser the time it takes....
1cm-------------------61*2^2=61*4=244.
4/3cm-------------------61*4*3*3/4*4=549/4
total time taken is 1/61 + 1/244 + 4/549 =36+9+16/61*4*9=1/36..
36 mins will be taken.

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divya aiswarya ravali.jonnalagadda  (9 years ago)

mr.siripally abinay in the problem it was told that that the square of the diameter is proportional so we have to square that

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Anurag Yadav  (10 years ago)

Y vivek ?
Time taken would be inversely proportional to dia^2. Hence I think time taken wud b 1/t=1/61+16/(9*61) + 4/61 = 9 min

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Sangita Sarkar  (9 years ago)

ans will be 9 mins

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saripalli abhinay  (9 years ago)

SIMRAN will you please tell me why you square the diameter of pipe

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