Latest Others Aptitude Question SOLUTION: A person travels at 30 kmph reaches his office 10 mins late by traveling with a speed of 40 kmph he reaches his ofiice 5 mins early.find out the distance between his home and offic

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(#M40033057) OTHERS Numerical Ability question time and distance Keep an EYE

A person travels at 30 kmph reaches his office 10 mins late by traveling with a speed of 40 kmph he reaches his ofiice 5 mins early.find out the distance between his home and office

Asked In Others venkatesh torahatula (10 years ago)

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Read Solution (3) :

Snehasis  (10 years ago)

If he's in the speed of 30 km/h he reaches 10 mins late and if he's in the speed of 40 km/h then he reaches 5 mins earlier. So. there's a time gap of 15 mins in arrival times.

This can be solved through a simple formula,

Required Distance = Product of the speeds/Difference of the speeds * Difference of time gap in arrival

Distance = 40 * 30/40 - 30 * 15/60

= 30 km

Therefore the distance between the home and office is 30 km.


ANOTHER METHOD :

Let the distance be x km.
Time taken to cover x km at 30 km/h = x/30 hrs
Time taken to cover x km at 40 km/h = x/40 hrs

Difference between the time taken = 15 min = 1/4 hrs

Therefore, x/30 - x/40 = 1/4 => x = 30

So, the required distance is 30 km.

Is this solution Helpfull? Yes (5) | No   

kshitij vashist  (10 years ago)

Let the distance b/w his home and office be x
while travelling at 30kmph he reaches 10min late:-
speed=distance/time
30=x/t+(10/60)
6x-180t=30 - (1)
Travelling at a speed of 40kmph reaches 5 min Early
40=x/t+(1/12)
12x-480t=-40 - (2)
on solving equation (1) and (2)..
we get t=10/20
and x=30
so distance is 30km

Is this solution Helpfull? Yes (1) | No   

ganesh chemanchula  (10 years ago)

30(t+0.16)=40(t-0.08) by solving we get t=0.8
distance=30*0.96=28.8 kms

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