Latest Infosys Aptitude Question SOLUTION: . X Z Y+X Y Z = Y Z X. Find the three digits

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(#M40033399) INFOSYS Numerical Ability question p Keep an EYE

. X Z Y+X Y Z = Y Z X.
Find the three digits

Asked In Infosys Mamata Sahu (10 years ago)

Solved RAKESH Read Solution (10)

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Read Solution (10) :

RAKESH  (10 years ago)

2nd column, z+y=z shows a carry so, z+y+1=10+z => y=9
1st column, x+x+1=9 => x=4 so, z=5

459+495=954

x=4,y=9,z=5

Is this solution Helpfull? Yes (77) | No (4)  

richa tailang  (10 years ago)

m not getting dis soln can u explain..?

Is this solution Helpfull? Yes (17) | No (5)  

Mukesh Nayal  (10 years ago)

Answer is:x=4,y=9,z=5.
1)X+X is giving Y,which means a no less than 10 which implies that X could be 4 maximum.
2)putting X=4(firstly),so we have sum up Y+Z=X,which means Y and Z can be 9 or 5,8 or 6.
3)taking Z=9 and y=5, we get X=4 and 1 carry.
4)Next,Z+Y=Z,which 9+5+1=15.
5)finally X+X+1=9.
Hence solved.

Is this solution Helpfull? Yes (7) | No (1)  

ESKILLA SATHISH  (10 years ago)

How u guys are assigning the numbers to the alphbts.........still im confusing..

Is this solution Helpfull? Yes (5) | No (1)  

DEEPAK KUMAR  (10 years ago)

439
+493
-----
932

Is this solution Helpfull? Yes (1) | No (7)  

Basant Das  (10 years ago)

xzy
+xyz y+z=x n z+y=z both gives diffrnt value i.e both expression giving
------ carry .hence, i> y+z= 1x(two digit) ii> z+y+1= 1z(two digit)
yzx iii>x+x+1=y
z+y+1=1z => 1z-z=y+1 => y=9......
from eq iii. x+x+1=9 =>x=4......
y+z=1x =>y+z=14 =>z=14-9 =>z=5.......

Is this solution Helpfull? Yes (1) | No (2)  

Ritu Mehandiratta  (10 years ago)

plz explain

Is this solution Helpfull? Yes | No (3)  

meda lakshmi naga sindhura  (9 years ago)

2x=y,z+y=y+z=z=x z+2x=x so only possible value 0
x=y=z=0

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suganyasekar  (9 years ago)

pls....give clear explanation ...frds

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vinita kumari  (9 years ago)

x must be 4 because (x+x)

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