Latest Infosys Aptitude Question SOLUTION: 3,4,7,10,13,16,19,22,find 10th term in series

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(#M40033485) INFOSYS Logical Reasoning question Keep an EYE

3,4,7,10,13,16,19,22,find 10th term in series

Asked In Infosys Nalini Vemula (11 years ago)

Solved RAGHAVA Read Solution (25)

Is this Puzzle helpful?   (27)   (17) Submit Your Solution Number Series

Read Solution (25) :

RAGHAVA  (11 years ago)

3
3*1=3+1=4
3*2=6+1=7
3*3=9+1=10
3*4=12+1=13
3*5=15+1=16
3*6=18+1=19
3*7=21+1=22
3*8=24+1=25
3*9=27+1=28

10th term = 28

Is this solution Helpfull? Yes (21) | No (1)  

shivakumar  (11 years ago)

n+3=22+3+3=28

Is this solution Helpfull? Yes (18) | No (1)  

roushan kumar  (11 years ago)

29
alternate prime no.s--->> 1st no. alternate && +6 diff. in alternate no.s starting frm 2nd no.

Is this solution Helpfull? Yes (7) | No   

Sudeepta Das  (11 years ago)

3+4= 7
3+7 =10
3+10 = 13
3+13 = 16
3+16 = 19
3+19 = 22
3+22 = 25

hence the series 3, 4, 7, 10, 13, 16, 19, 22, 25

Is this solution Helpfull? Yes (3) | No (1)  

Purnendu Podder  (11 years ago)

Was 34 an option? if it was in the options, den i gues, 34 is d ans.
1st term -> 3 (could not gues the logic for 3 being the 1st term)

2nd term -> 4=3*[1]+1 (1 is an ODD number)

3rd term -> 7=3*[2]+1 (2 is an EVEN number)

4th term -> 10=3*[3]+1 (3 is an ODD & PRIME number)

5th term -> 13=3*[4]+1 (4 is an EVEN number)

6th term -> 16=3*[5]+1 (5 is an ODD & PRIME number)

7th term -> 19=3*[6]+1 (6 is an EVEN number)

8th term -> 22=3*[7]+1 (7 is ODD & PRIME number)

9th term -> 25=3*[8]+1 (8 is an EVEN number)

10th term -> either 28=3*[9]+1 (9 is the next ODD number)
or 34=3*[11]+1 (11 is the next ODD & PRIME number)
Now its up to you, whether to place 9 or 11 in [ ]. If you place 9, den the ans. is 28 which was not in the options and if you place 11, den you have to consider that 1 is an ODD & PRIME number while calculating the 2nd term.

Is this solution Helpfull? Yes (2) | No (1)  

MANU  (10 years ago)

4+6=10
10+6=16
16+6=22
22+6=28
ANS====28

Is this solution Helpfull? Yes (2) | No   

AMAN PATIL  (6 years ago)

Here is another way....
all has prime number but alternate substraction by 1
3
5-1=4
7
11-1=10
13
17-1=16
19
23-1=22
29
31-1=30
So by this method... the answer is 30.

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SAGAR TRIPATHI  (11 years ago)

but 28 was not on the options
nearest was 30 and 31??

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Jaya Das  (11 years ago)

10th term is 28

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Gaurabh Khugshal  (10 years ago)

9th term is 29 by skipping prime numbers.
10th term is 32.

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Avinash Kumar  (11 years ago)

ans will be 30

Is this solution Helpfull? Yes | No (1)  

Soumyodeep Karmakar  (11 years ago)

25 is the answer....
7-4=3
10-7=3
.....
.....
22-3=19
22+3=25
ie 35-3=22

Is this solution Helpfull? Yes | No (2)  

chandra prakash  (11 years ago)

23
As Series starts with prime number and then a even number and so on... prime number just next to 19 is 23 and hence the answer.

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shiva  (11 years ago)

31 by skipping next prime number and adding three

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manish  (11 years ago)

3*1+0=3
3*1+1=4
3*2+1=7
3*3+1=10
3*4+1=13
3*5+1=16
3*6+1=19
3*7+1=22
3*8+1=25
so 25 is the answer

Is this solution Helpfull? Yes | No (5)  

Shreya Nama  (11 years ago)

Sum of left most digit and right most digit=next digit on right side
3+4=7
3+7=10
3+10=13
3+13=16
3+16=19
3+19=22
3+22=25
3+25=28 --> 10th term

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esha dian  (10 years ago)

3*1+1
3*2+1
3*3+1
3*4+1
in this way we have to proceed
and last
3*8+1
ans is 25

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esha dian  (10 years ago)

3*1+1
3*2+1
3*3+1
3*4+1
in this way we hv to proceed
and last
3*10+1
ans is 31

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piyush prabhat  (10 years ago)

ans is 28
3+4 =7
3+7=10
3+10=13
3+13=16
3+16=19
3+19=22
3+22=25
3+25=28
3+28=31
3+31=34

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P.R.PRATHAP  (9 years ago)

58.........

Is this solution Helpfull? Yes | No (1)  

vamshi  (7 years ago)

The series is in Arithmatic progression for 8th term

t8=a+(n-1)d

a=3
n=8
d=3

sub we get t8=28

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Vikas Kumar  (7 years ago)

61..
this is answer

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Vaish  (7 years ago)

3+1=4
4+3=7
7+3=10
.

28+3=31

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Srikanth Atthota  (6 years ago)

if we observe carefully we can split the series into two parts
first part is alternate prime numbers ----- 3,7,13,19
second part is increasing even values with a value of 6 ------4,10,16,22
in the given series the last number is 22,so the next number in the series would be alternate prime number after 19 i.e., 29
so the answer is 29

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  (6 years ago)

Question : 3,4,7,10,13,16,19,22,___,____,....find 10th term in the series
Solution : (1) Prime Number are : 2,3,5,7,11,13,17,19,23,29,....in this series they took the alternate
numbers like 3,7,13,19,29,... so here the 9th term will be 29,..
(2) remaining numbers in the questions are 4,10,16,22,.... so here
2x2=4,2x5=10,2x8=16,2x11=22,...here they left 2x3=6,2x4=8, then they include again
2x5=10 again they left number 12,14,...so on,...so at last the answer will be 28,...
Answer :3,4,7,10,13,16,19,22,29,28,...here the 10th term is 28 ,.

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