Latest TCS Aptitude Question SOLUTION: Find the value of "n" where 348 + 31996 +33943+33n.

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(#M40033586) TCS Numerical Ability question Keep an EYE

Find the value of "n" where 348 + 31996 +33943+33n.

Asked In TCS (10 years ago)

Unsolved Read Solution (6)

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jeeva   (10 years ago)

(3^16 ) ^3+3^1996+3^3943+(3^n)^3
So it is equivalent to a^3+3a^2b+3ab^2+b^3
So,3*(3^16)^2*3^n=3^1996
3^(33+n)=3^1996
n=1963

Is this solution Helpfull? Yes (12) | No (7)  

anjali raj  (9 years ago)

this question is wrong d correct question is 3^48+3^1996+3^3943+3^3n.....solved below by jeeva

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Ritu Jha  (9 years ago)

jeeva pls explain properly

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Abdul Jabbar  (4 years ago)

Right question is 3^48+3^1996+3^3943+3^3n
so check the difference b/w to power 1996-48=1948.
again check then we will get 3943-1996=1947.
so here we can see that the difference b/w 1st two power and 2nd two power decreased by 1.
so we can write for 3rd power i.e.
3n-3943=1946
n=1963 answer

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ritika  (7 years ago)

my ans is
33910

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D Gokila Dharani  (5 years ago)

I request anybody to explain this problem clearly

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