Latest TCS Aptitude Question SOLUTION: Q). If there are 254 barrels out of which one is poisoned, if a person tastes very little he will die within 14 hours so if there are mice to test and 24 hours to test, how many m

• Placement Papers
• /
• TCS
• /
• Numerical Ability
• /
• Data Sufficiency

TCS Question Papers: TCS Interview Experience(90) TCS Company Profile

(#M40033670) TCS Numerical Ability question Keep an EYE

Q). If there are 254 barrels out of which one is poisoned, if a person tastes very little he will die within 14 hours so if there are mice to test and 24 hours to test, how many mice are required to find the poisoned barrel ?

1) 3
2) 2
3) 6
4) 8

Asked In TCS ravikiran (10 years ago)

Unsolved Read Solution (15)

Is this Puzzle helpful?   (8)   (2) Submit Your Solution Data Sufficiency

Read Solution (15) :

sai kiran  (10 years ago)

2^8=256>254.....ans=8

Is this solution Helpfull? Yes (14) | No (3)  

vaibhav agarwal  (10 years ago)

ans is 1...

lets start with 1 mice...

mice taste 1st bottle at 1st min.....he will die if it is poisoned after 14 hrs.
again same mice taste at 2nd min....he will...............after 14hrs 1 min.
again same mice taste at 3rd min....he will...............after 14hrs 2 min.
again same mice taste at 4th min....he will...............after 14hrs 3 min.
again same mice taste at 5th min....he will...............after 14hrs 4 min..
.
.
.
..
.
.
.
.
.
again same mice taste at 253th min....he will...............after 14hrs 252 min.
and if still mice didnt die then last 254th barrel is poised...

acc. to time we can judge which barrel is poisoned...
so minimum mice requirement is 1....answer is 1

Is this solution Helpfull? Yes (13) | No (7)  

kulwant singh  (10 years ago)

suppose there are 4 barrels
suppose we have 4 bottle
we will allow first mouse to drink from first 2 bottle and 2nd mouse from last 2 bottle.
if first mouse died then first bottel is poisoned and 2nd died then 3th bottle is poisoned. if both died then poison is in 3 bottle. and if no one dies poisen is in 4th bottle.

so for 4bottle 2mouse are required 2^n is the number of bottle and n is the number of mouse 4bottle ,2mouse

Is this solution Helpfull? Yes (4) | No (4)  

kulwant singh  (10 years ago)

this on is correct
suppose we have 4 bottle
we will allow first mouse to drink from first 2 bottle and 2nd mouse from 2nd and 3rd bottle
if first mouse died then first bottel is poisoned and 2nd died then 3th bottle is poisoned. if both died then poison is in 2nd bottle. and if no one dies poisen is in 4th bottle.

so for 4bottle 2mouse are required 2^n is the number of bottle and n is the number of mouse 4bottle ,2mouse

Is this solution Helpfull? Yes (3) | No (1)  

kulwant singh  (10 years ago)

suppose there are 4 barrels
suppose we have 4 bottle
we will allow first mouse to drink from first 2 bottle and 2nd mouse from 2nd and 3rd bottle.
if first mouse died then first bottel is poisoned and 2nd died then 3th bottle is poisoned. if both died then poison is in 3 bottle. and if no one dies poisen is in 4th bottle.

so for 4bottle 2mouse are required 2^n is the number of bottle and n is the number of mouse 4bottle ,2mouse

Is this solution Helpfull? Yes (1) | No   

Sri Reddy  (10 years ago)

vaibhav agarval solution is absolutely correct...:)

Is this solution Helpfull? Yes (1) | No (5)  

shreyasi chanda  (10 years ago)

can u plz explain the logic

Is this solution Helpfull? Yes | No (1)  

benasir fathima  (10 years ago)

pls explain..

Is this solution Helpfull? Yes | No   

kulwant singh  (10 years ago)

this on is correct
suppose we have 4 bottle
we will allow first mouse to drink from first 2 bottle and 2nd mouse from last 2 bottle.
if first mouse died then first bottel is poisoned and 2nd died then 3th bottle is poisoned. if both died then poison is in 2nd bottle. and if no one dies poisen is in 4th bottle.

so for 4bottle 2mouse are required 2^n is the number of bottle and n is the number of mouse 4bottle ,2mouse

Is this solution Helpfull? Yes | No (1)  

KOLLI VASANTHI  (10 years ago)

pls explain it in detail

Is this solution Helpfull? Yes | No   

raghavendra  (9 years ago)

data is not sufficient

Is this solution Helpfull? Yes | No   

Vithiya  (9 years ago)

Its 8.

An old puzzle

Call barrel 1 as 00000001
Barrel 2 as 00000010
Barrel 3 as 00000011
.
.
Barrel 254 as 11111110

Now, call mouse 8 as 2^7, mouse 7 as 2^6, mouse 6 as 2^5, ...... and mouse 1 as 2^0

Mouse 1 should drink from all those cans having digit at place 2^0 as 1, mouse 2 should drink from all those cans having digit at place 2^1 as 1, similarly for mouse 3, 4, 5, 6, 7 and 8

Now, suppose mice 1, 2, 3 die, then barrel 00000111 is poisoned, i.e, barrel 7 is poisoned

Is this solution Helpfull? Yes | No   

prasannalatha  (9 years ago)

Please explain logic in detail

Is this solution Helpfull? Yes | No   

Manthan Patel  (9 years ago)

2^8=256>254
so 8
256-254=2
8-2=6
so ans =6

Is this solution Helpfull? Yes | No   

Aparrna  (9 years ago)

2^8=256

so ans is 8

Is this solution Helpfull? Yes | No   

Please Login to Read Solution.