Latest TCS Aptitude Question SOLUTION: A can complete a piece of work in 8 hours, B can complete in 10 hours and C in 12 hours. If A,B, C start the work together but A laves after 2 hours. Find the time taken by B and C

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(#M40033753) TCS Numerical Ability question Keep an EYE

A can complete a piece of work in 8 hours, B can complete in 10 hours and C in 12 hours. If A,B, C start the work together but A laves after 2 hours. Find the time taken by B and C to complete the remaining work.

1) 2 (1⁄11) hours
2) 4 (1⁄11) hours
3) 2 (6⁄11) hours
4) 2 hours

Asked In TCS ravikiran (10 years ago)

Solved Mounika Dantuluri Read Solution (22)

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Read Solution (22) :

Mounika Dantuluri  (10 years ago)

A,B,C 1 hour work is=1/8+1/10+12= 37/120
A,B,C work together for 2 hours, so,A,B,C 2 hours work is: (37/120)*2=37/60
remaining work=1-37/60=23/60 (23/60 work is done by B and C together)
B,C 1 hour work is= 1/10+1/12=11/60
23/60 hours work done by B,C= (11/60)* (60/23)=11/23
so... ans is: 2(1/11)

Is this solution Helpfull? Yes (57) | No (6)  

keerthana  (10 years ago)

total unit of the work is 120units
In 1 hour A can complete 15units
In 1 hour B can complete 12units
In 1 hour C can complete 10units
In 1 hour A+B+C can complete 37units
Therefore in 2 hours A+B+C would have completed 74units
Remaining work to be completed is 12-74=46
In 1 hour B+C can complete 22units
Therefore time taken to complete the remaining job =46/22=23/11=2(1/11)
ans is 2(1/11)

Is this solution Helpfull? Yes (37) | No (1)  

NISHANT AGARWAL  (10 years ago)

1)2(1/11)hours

The time taken by A+B+C to do the work is (1/8+1/10+1/12)=37/120
work done by ABC in 2 hours = (37/120) x 2 = 37/60
there work left = 1-(37/60) = 23/60

B+C can complete the work in = ( 1/10+1/12 )= 11/60

therefore time taken by BC = 11/60 x 60/23 = 23/11 = 2(1/11) hours

Is this solution Helpfull? Yes (4) | No   

archita chaudhuri  (10 years ago)

a=1/8
b=1/10
c=1/12
a+b+c=1/8+1/10+1/12
=(15+12+10)/120
=37/120 [in 1 hr]
In 2 hr,work done=37/60
work left=1-37/60
=23/60
b+c=1/10+1/12
=(6+5)/60
=11/60
time taken by b and c=23/60 x 60/11
=23/11
=2(1/11) hr

Is this solution Helpfull? Yes (4) | No (2)  

Arun  (8 years ago)

A leaves after 2 hours=2/8
B=x/10
C=x/12
Total work=1
2/8+x/10+x/12=1
After solving we get x=45/11
Ans=4(1/11)hrs

Is this solution Helpfull? Yes (2) | No (6)  

Kavitha N  (7 years ago)

One day work of A : 1/8
One day work of B : 1/10
One day work of c : 1/12
A,B,C work together for 2 days : 37/120*2
37/60
Remaining work : 1-37/60
23/60
B and C work together to do the remaining work :60/11*23/60
23/11
2(1/11)hours

Is this solution Helpfull? Yes (2) | No   

suraj kamat  (4 years ago)

A,B,C 1 hour work = 1/8+1/10+1/12=37/120
A leaves after 2 hour so total time required to complete the work is:
2/8+X/10+X/12=1
15+6X+5X=60
X = 4(1/11)

but question is Find the time taken by B and C to complete the remaining work so we subtract the A's 2 hours work .
so X=4(1/11)-2
X=2(1/11) Hours.

Is this solution Helpfull? Yes (2) | No   

Asmita Raha  (10 years ago)

Ans : 2(1/11)

Is this solution Helpfull? Yes (1) | No (4)  

Girish Jambkar  (10 years ago)

Option A
1hr work of all three=37/120
2hr work=37/60,
work left=23/60,
efficiency of b & c =11/60
work left = (23/60)/(11/60)
Ans=2(1/11)

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Aditya  (9 years ago)

2/8 +x/10 +x/12 =1

so x=4(1/11)

Is this solution Helpfull? Yes (1) | No (1)  

swarnalakshmi  (8 years ago)

total unit of the work is 120units
In 1 hour A can complete 15units
In 1 hour B can complete 12units
In 1 hour C can complete 10units
In 1 hour A+B+C can complete 37units
Therefore in 2 hours A+B+C would have completed 74units
Remaining work to be completed
(ie) (total work-work done) is120-74=46
In 1 hour B+C can complete 22units
Therefore time taken to complete the remaining job =46/22=23/11=2(1/11)
ans is 2(1/11)

Is this solution Helpfull? Yes (1) | No   

shivaprasad  (7 years ago)

2*(1/8)+x/10+x/12=1
22x/120=3/4
x=45/11
4(1/11)

Is this solution Helpfull? Yes (1) | No   

amar  (6 years ago)

Ans=4(1/11)hour
A=8hours,B=10hours,C=12hours
Total work A,B,C=LCM OF A,B,C=120work
A=120/8=15work/hour
B=120/10=12work/hour
C=120/12=10work/hour

Let total work =Xhour
A left in 2 hours
15(2)+12x+10x=120
X=4(1/11)hour

Is this solution Helpfull? Yes (1) | No   

Syed Ishtiaq  (10 years ago)

1/8+1/10+1/12 = 37/60

1-37/60=x(1/10+1/12)

solve for x

Is this solution Helpfull? Yes | No (2)  

ajit jha  (10 years ago)

aswer is 1

Is this solution Helpfull? Yes | No (6)  

Rahul Jaiswal  (8 years ago)

answer is 2)

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arun kumar ravi  (8 years ago)

A,B,C WORK in 2 hr is =2(1/8+1/10+1/12)

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arun kumar ravi  (8 years ago)

A,B,C work in 2 hr is = 2(1/8+1/10+1/12)= 37/60
remaining work is 1-37/60=23/60
let x be total no days to complete a work by B,C
x(1/10+1/12)=23/60
x=23/11 --------------------------- x=2(1/11)

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srikanth  (7 years ago)

2(1/11)hrs

Is this solution Helpfull? Yes | No (1)  

Mamatha AC  (7 years ago)

work done by A+B+C in 2 hours is 37/60
so remaining work is 1-37/60=23/60
work done by B+C in 1 hour is 11/60
so the remaining work done by B+C is 2(1/11) hours.

Is this solution Helpfull? Yes | No (1)  

Tavleen arora  (5 years ago)

A-->8hrs
B-->10hrs
C-->12hrs

assume total work done to be=120units(l.c.m of all 3 time)

rate of work of A= 120/8=15units/hr
rate of work of B= 120/10=12units/hr
rate of work of C= 120/12=10units/hr
total rate of A,B and c=15+12+10=37units/hr
i.e,
In 1 hour=37units is done by a,b,c
So, in 2 hours=74units of work is done by a,b,c

120-74=46units is the reaming work left to be done by B and C

in 1 hr B and C takes 32units of work(12units/hr+10units/hr)
So, in 2(1/11)hrs ,46 units of work is done

ANS=2(1/11)

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Gayathri Praharshitha  (4 years ago)

Answer is (1) 2 (1/11)

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