Latest TCS Aptitude Question SOLUTION: In a certain code language ‘UMBRELLA’ is written as ‘11113218512121’; and as ‘VULNEERABLE’ ‘112111121451812125’. How is ‘YTTERBIUM’ written in that code? 1)

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In a certain code language ‘UMBRELLA’ is written as ‘11113218512121’; and as ‘VULNEERABLE’ ‘112111121451812125’. How is ‘YTTERBIUM’ written in that code?


1) 111110110518291111
2) 115110110518291113
3) 113110110518291113
4) None of these

Asked In TCS sravani (10 years ago)

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suraj hegde  (10 years ago)

here u=21 is written as 111, v=22 is written as 112 so considering this y=25 must be 115.hence option 2.

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RAKESH  (10 years ago)

UMBRELLA---->111/13/2/18/5/12/12/1
VULNERABLE---->112/111/12/14/5/18/1/2/12/5
the corresponding letter which will be represented by backslash and the number will be noted.after matching it and form a code for YTTERBIUM which will be formed and there is no code for I and compare the code without putting I value in the given solution.
so finally 115110110518291113

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Surbhi Verma  (10 years ago)

Option no.2 is correct

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farhan ahmad  (10 years ago)

The answer is option 3...because wen counting from back with alphabetical number giving a=1 b=2............z=26, we get the answer but the tricky part is that starting number 111=U(given in first example in question), as same as 112=Y, so as them 113=Z which is the third option

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chaitra  (10 years ago)

option 2

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Bhargava Mani Chandramsh Pothamsetty  (10 years ago)

115110110518291113

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Umabandekar  (9 years ago)

The answer is 4 (none of these) because
113/110/110/5/18/2/9/111/3 - Y/T/T/E/R/B/I/U/M (note :here m )is not representing as 13 it is just coding as 3 it is wrong. so answer is none of these

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Gottiparthi Shiva Sandeep Kumar  (8 years ago)

UM=11113
YTTERBIUM="Something"+11113;
In above word UM=11113;
But in options A,B,C nothing will be at last 11113..So None of this..simply..
Don't waste time for this time of qns by going deep thing :)

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